I need help with a pretty simple program please

okay this is what i have:

#include <stdio.h>
main()
{
float clock_num; /*Employee clock number*/
float hrs_worked;
float hrly_wage;
float gross_pay;

printf("Enter the clock number:");
scanf("%f",&clock_num);
printf("Enter your hourly wage:");
scanf("%f",&hrly_wage);
printf("Enter number of hours worked:");
scanf("%f",&hrs_worked);


gross_pay=hrs_worked*hrly_wage;

printf("Your gross pay is $%i\n", gross_pay);
}



but he wants it like this:

-------------------------------------------
clock # wage hours gross
-------------------------------------------
384243 10.60 51.0 540.60

(FYI: the clock number is just random, it doesnt have anythign to do with the calculation)

i just can't seem to get the cursor to do what i want it to do. please help. thanks!

can anyone help?

#include <stdio.h>
int main()
{
long clock_num; /*Employee clock number*/
float hrs_worked;
float hrly_wage;
float gross_pay;


printf("Enter the clock number ( six digits) :");
scanf("%li",&clock_num);
printf("Enter your hourly wage:");
scanf("%f",&hrly_wage);
printf("Enter number of hours worked:");
scanf("%f",&hrs_worked);


gross_pay=hrs_worked*hrly_wage;

printf ("Clock # Wage Hours Gross\n\n");
printf("%li %4.2f %4.1f %.2f", clock_num,hrly_wage,hrs_worked,gross_pay);

return 0;
}

Remember I/O library in C is not reliable.
Here is my simple solution. Although it does not
exactly match with your intended purpose, but
this may give you a alternative to make input and
output on the same line.

#include <conio.h> /* for clrscr() */
#include <stdio.h>

int main()
{
float clock_num; /*Employee clock number*/
float hrs_worked;
float hrly_wage;
float gross_pay;

printf("Enter the clock number:");
scanf("%f",&clock_num);
printf("Enter your hourly wage:");
scanf("%f",&hrly_wage);
printf("Enter number of hours worked:");
scanf("%f",&hrs_worked);

gross_pay=hrs_worked*hrly_wage;

clrscr(); /* clear screen */
printf("clock # wage hours gross\n");
printf("%f%f%f%%f\n",clock_num,hrs_worked,
hrly_wage,gross_pay);
return 0;
}
Note: You need to setfield to align output in good format.(such as "%4.2f"..)
Hope it give you an idea!
DV007

Why is that no-one appears to check the return code from scanf()? Do we all trust the user that much?

Code:

---

if (scanf("%f", &myfloat) == 1)
    printf("You entered %f\n", myfloat);
else
    printf("Invalid!!\n");

---

course i always check return values.
but i thought best to restrict the answer to the level of the question.