current time

I tried printing out the current time on my computer through a character string, by using a pointer. The program works fine, except for one small glitch....it's not printing out the correct time. Instead it's printing out some day in January 2116. I figure it has to be somewhere in the code for the address of the current time.
Here's the code, maybe someone can show me where it went wrong.

Code:

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#include <stdio.h>
#include <time.h>

void GetTimeDate (void);

int main()
{
  printf("Before the GetTimeDate() function is called.\n");
  GetDateTime();
  printf("After the GetDateTime() function is called.\n");
  return 0;
}

/**********************************The GetDateTime function**************************************/

GetDateTime (void)
{
  time_t now;
  int i;
  char *str;
 
  printf("Within the GetDateTime() function.\n");
  time(&now);
  str = asctime(localtime(&now));
  printf("The current date and time is ");
  for (i=0; str[i]; i++)
      printf("%c", str[i]); 
}

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Nymph

I think this is because the asctime functione expects a struct tm argument and not a time_t (long).
You can use the localtime function (corrects for local time zone) to convert the time_t to a tm structure.

Code:

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void GetDateTime (void)
{
  time_t now;
  struct tm *newtime;
 
  printf("Within the GetDateTime() function.\n");
  time(&now); /* get time as long */
  newtime = localtime(&now); /* convert to local time */
 
  printf("The current date and time is: %s\n", asctime(newtime));
}

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Your function prototype is spelt incorrectly:

>void GetTimeDate (void);

Also, you function should be like this:

Code:

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void GetDateTime(void)
{ .........

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