Confusion in pointers in C

Hi all,
Here is another question for me that i could not find any answer. Try to create an dynamic array in C just using vscode in Ubuntu. Try to describe my issue in code sample below. When i run the code output is: [hello0][(null)]
When i use line 10 in code sample taking this error message "Exception has occurred Segmentation fault. Could you please tell me what i am doing wrong. I would be much appreciated.

Code:

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#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int foo(char ***BufferArray,char *item,int idx);
int main(){
    char **ptr=malloc(sizeof(char*)*3);
    char a[]="hello0";
    char b[]="hello1";
    foo(&ptr,a,0);
    //foo(&ptr,b,1);//Exception has occurred. Segmentation fault  - line 10
    printf("[%s]",*(ptr+0));
    printf("[%s]",*(ptr+1));
    getchar();
    return(0);
}

int foo(char ***BufferArray,char *item,int idx){
    int n;
    n=1;
    *(*(BufferArray+idx))=malloc(sizeof(char)*strlen(item));
    strcpy(*(*(BufferArray+idx)),item);
    return(0);
}

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Code:

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#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int foo(char ***BufferArray,char *item,int idx);
int main(){
    char **ptr=malloc(sizeof(char*)*3);
    char a[]="hello0";
    char b[]="hello1";

    foo(&ptr,a,0);
    foo(&ptr,b,1);
    printf("[%s]\n",*(ptr+0));
    printf("[%s]\n",*(ptr+1));

    free(ptr[0]);
    free(ptr[1]);
    free(ptr);
    return(0);
}
 
int foo(char ***BufferArray,char *item,int idx){
    *((*BufferArray)+idx)=malloc(sizeof(char)*(strlen(item)+1));
    strcpy(*((*BufferArray)+idx),item);
    return(0);
}

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Two things.
1. You forgot to count the \0 when allocating space for the string.
2. You need to dereference BufferArray and then index it.

BufferArray points to ptr in main, and you want to effectively do ptr[idx] = malloc...

Writing it like this saves a bunch of stars and brackets.

Code:

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    (*BufferArray)[idx]=malloc(sizeof(char)*(strlen(item)+1));
    strcpy((*BufferArray)[idx],item);

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