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Hi,
I have to make a program that reads numbers from a file. Then, it has to store them in an array and, finally, it has to print the numbers.
I'm a beginner and every program I make it fails.
How would you make this program? It's C programming.
Thank you so much.
You will need to show us your first attempt. We can then guide you. Don't try to do it all in one attemptQuote:
Originally Posted by AnthonyBin
Start with just opening and closing the file.
Then create the array.
Then read values into the array.
Then print the values.
Does the file exist or are you creating the file?
What is the structure of the file?
Binary day or numbers as text?
Are they integer numbers or floating point numbers?
Are there any restrictions as to what functions to use to input the data?
Good luck!
Thank you for replaying.
The file I'm using exists. It contains integer numbers just like this:
1
5
65
3
There are no restrictions but it should be simple.
I think there is no problem when opening the file. I think the mistake is afterwards.Code:
int main(){
FILE *data;
int array[100],i=0,j,k;
data=fopen("data.txt","r");
if(data==NULL){
printf("There was a mistake\n");
exit(1);
}
do{
j=fscanf(data,"%d",array[i++]);
}while(j!=EOF);
for(k=0;k<sizeof(array);k++){
printf("The value os the array in the position %d is %d\n",k,array[k]);
}
return 0;
}
Thank you so much.
Please see my changes:
Usually avoid do-while, and use while or for loops instead.Code:#include <stdio.h>
#include <stdlib.h>
#define DIM 100 // Use #defines rather than "Magic Numbers"
int main(){
FILE *data = NULL; // Always initialize all variables
int array[DIM] = {0}; // I would recommend putting each on separate lines
int count = 0; // Count of data input, instead of i
int j = 0;
int k = 0;
data=fopen("data.txt","r");
if(data==NULL){
printf("There was a mistake\n");
exit(1);
}
/*
do{
j=fscanf(data,"%d",&(array[i]));
i++;
}while(j!=EOF);
*/
while(1)
{
j=fscanf(data,"%d",&(array[count])); // or array + count
if(j == EOF)
{
break;
}
count++;
}
// for(k=0;k<sizeof(array);k++){ // sizeof(array) != number of elements
for(k=0; k < count; k++){
printf("The value os the array in the position %d is %d\n", k, array[k]);
}
return 0;
}
No reason to print out 100 integers to display the data in only 4 elements.
Use more descriptive names for all variables other than loop variables
if your compiler can, use for(int k = 0; k < count; k++)
j could be be more descriptive as well (ret, retval, etc...)
Note my other comments in the code.
You should also be checking to insure that you don't overflow the array bounds for the read.
Yes, of course, and the while() loop could be replaced with a for() loop.Quote:
Originally Posted by jimblumberg
Code:for (i = 0; i < DIM; ++i) {
j=fscanf(data,"%d",&(array[count])); // or array + count
if(j == EOF)
{
break;
}
count++;
}
Closing the file might be a good idea as well ;)
My attempt would probably look like that
Code:#include <stdio.h>
#define DIM 100
int main(void)
{
FILE *data = fopen("data.txt", "r");
if(data == NULL)
{
printf("There was a mistake\n");
return 1;
}
int array[DIM] = {0};
int count = 0;
for (; count < DIM; ++count)
{
if(EOF == fscanf(data, "%d", &(array[count])))
{
break;
}
}
fclose(data);
for(int idx = 0; idx < count; ++idx)
{
printf("The value os the array in the position %d is %d\n", idx, array[idx]);
}
return 0;
}
Excuse me, rstanley, but in your first code, why do you use 1 in "while(1)"?
Thank all of you for being such nice! :)
while(1) created an infinite loop. There must be a test in the code to "break" or end the loop.
I later realized that the for() loop was a better choice to prevent an overrun of the end of the array.
You're welcome!