view memory location of variable

Is it possible to view memory location of variable in visual studio without printf statement

Code:

---

#include<stdio.h>


#define size  5
#define set  1
#define Reset 0

int flag1;

struct Node1
{
    int Number1;
    char Rank1;
    float price1;
    double salary1;
    char Name1[5];
    int* ptr1;
}svar;

union Node2
{
    int Number2;
    char Rank2;
    float price2;
    double salary2;
    char Name2[size];
    int* ptr2;
}uvar;


void wait()
{
    for (int i = 0; i < 10; i++);
}


void foo1(int* PTR)
{
    *PTR = 100;


}


void foo2()
{
    flag1 = set;
    wait();
    flag1 = Reset;


}


int main()
{
    int Number;
    char Rank;
    float price;
    double salary;
    char Name[size];
    int *ptr;


    Number = 2;
    printf("%d", &Number);
    Rank = 'A';
    price = 230.23;
    salary = 44000.540;
    //Name[size] = "VIJA";
    ptr = &Number;


    svar.Number1 = 10;
    svar.Rank1 = 'B';
    svar.price1 = 540;
    svar.salary1 = 11240;


    uvar.Number2 = 20;
    uvar.Rank2 = 'C';
    uvar.price2 = 740;
    uvar.salary2 = 12240;


    foo2();


    if (Rank == 'A')
    {
        printf("success");
    }
    else
    {
        printf("fialure");
    }


    foo1(&Number);
       
    return 0;
}

---

Attachment 16495

Can't you just write &Number in the address bar of the memory display?

Quote:

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Originally Posted by Salem

Can't you just write &Number in the address bar of the memory display?

---

I get two different memory location of variable

print statement display memory location 1383070532 of Number on terminal

address bar display of memory 0x000000633418F744 of Number

confused because there should be only one memory location Number

Attachment 16497

Well there is only one address.

Your %d is the wrong format for displaying addresses.
1. It's in decimal, so that's a source of confusion.
2. Your addresses are 64-bit, so most likely you're only seeing the lower 32 bits when printing it at a decimal integer - yet more confusion.

Try it with

Code:

---

printf("%p\n", (void*)&Number);

---

Quote:

---

Originally Posted by Salem

for displaying addresses.

Try it with

Code:

---

printf("%p\n", (void*)&Number);

---

---

yes it worked, Now the problem is that there can be many variables in a program like we can see the value of all the variables at once in the watch window, can I see all the memory locations at once

Now every time I enter the address of the variable in the memory address bar, only then I get its location. I can't see all memory address

TBH, the address of a variable is seldom as interesting as it's contents.

Once the stack frame is established, your local variables never change address, but their contents will change.

Some local variables might not even have allocated space due to compiler optimisations, yet the debugger will be able to determine the value of the variable just fine.

For globals, there's also this option.
/Fm (Name Mapfile) | Microsoft Docs

> can I see all the memory locations at once
Your memory dump is looking at several hundred bytes of memory.
What you don't have is a clear association of which bits of memory correspond to which variable.

For example, given

Code:

---

int main()
{
    int Number;
    char Rank;

---

Knowing the address of Number tells you nothing about the address of Rank.

For sure, you'll learn a few 'tricks' given the current compiler.
But change compiler, and the 'rules' as to how the compiler chooses to layout local variables on the stack are likely to change.