Problem using getchar

Hello,
On my program I have 9 char named c1,...c9.
During the program, I write: gtch=getchar() (I should give a number between 1 and 9)

How can I modifiy the "value" of the character c1,...9 according to what number I enter?

For example, c4= 'x'. Then, I enter the number 4, so gtch='4'. How can I transform c4 to 'y'.

PS: I'm a begginer on C...

Thank you !

> On my program I have 9 char named c1,...c9.
Rather than doing
c1, c2, c3 etc

you use an array instead.

Code:

---

char c[9];

---

This gets you 9 chars labelled c[0] to c[8];

So perhaps for an easier life in this case

Code:

---

char c[10];

---

This gets you 10 chars labelled c[0] to c[9];


> During the program, I write: gtch=getchar() (I should give a number between 1 and 9)
This will get you a character '1' to '9'

To transform a single digit character containing a number into an integer, all you do then is
gtch = gtch - '0';

You can then do
c[gtch] = 'y';

Thank you for your quick answer !
I still have a small error:
Here's what I write (whithout details):

Code:

---

char cases[10]={'x0','x1',...'x9'};
int main (void)
    ...
    char gtch;
    gtch=getchar();
    gtch=gtch-'0';
    cases[gtch]='y';  --> in this line I have an error: array suscrpit has type char , so when I run my program no 'y' is visible.

---

Thank you for your time !

Well getchar() actually returns an int, so you should really have

Code:

---

int gtch;
gtch=getchar();
if ( gtch != EOF ) {
    gtch=gtch-'0';
    cases[gtch]='y';
}

---

Also, things like 'x0' are not characters, since you have two chars between single quotes.

I understand the problem, Thank you !:)