Error in loop, simple program error, replace int with int

Code:

---

#include <stdio.h>
#define LIMIT_2 28

/* j, k, l, m, n, o */

int main (void)
{
    int p = 0;

    char alphabet[LIMIT_2] = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'w', 'y', 'z', '\0' };

    char array[ ] = { 'A', 'B', 'C', 'D', 'E', 'F', '\0' };
    int k_2 = 61;
    int x = 97;
    int u = 0;

    while (p <= 26 && k_2 <= 79) // k_2 <= 79   
    {
        while (x <= 123 && p <= LIMIT_2) // while <= 123
        {
            printf("\n%c\t%d", alphabet[p], k_2);
            p++;
            k_2++;

            if (k_2 == 69)
            {
                while (u <= 5)
                {
                    printf("\n7%c", array[u]);
                    u++;
                }
            }

        printf("\t%d\t", x);
        x++;
        }

        printf("\n");
    }

    return 0;
}

---

Please, what would be the best way to output "6A, 6B, 6C, 6D, 6E, 6F" inside the second column after 69? Any other bugs I will fix by myself.

https://www.rapidtables.com/code/text/ascii-table.html

The best way is to use the %x format, rather than trying to mung something yourself with a separate loop.

Code:

---

#include <stdio.h>

int main ( ) {
  for ( int c = 'g' ; c <= 's' ; c++ ) {
    printf("%c %d %X %x\n", c, c, c, c);
  }
}

$ gcc bar.c
$ ./a.out
g 103 67 67
h 104 68 68
i 105 69 69
j 106 6A 6a
k 107 6B 6b
l 108 6C 6c
m 109 6D 6d
n 110 6E 6e
o 111 6F 6f
p 112 70 70
q 113 71 71
r 114 72 72
s 115 73 73

---

> char array[ ] = { 'A', 'B', 'C', 'D', 'E', 'F', '\0' };
You get the same thing with
char array[] = "ABCDEF";
Consider that for your whole alphabet string.