Can someone please guide me I want to make this program to ask denomination .

Code:

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#include<stdio.h>
#include<conio.h>
int main()
{
    long amount;
    long note5000, note1000, note500, note100, note50, note20, note10, coin5, coin2, coin1;
    clrscr();



    note5000 = note1000 = note500 = note100 = note50 = note20 = note10 = coin5 = coin2 = coin1 = 0;




    printf("Enter the amount: ");
    scanf("%ld", &amount);




    if(amount >= 5000)
    {
    note5000 = amount/5000;
    amount -= note5000 * 5000;
    }
    if(amount >= 1000)
    {
    note1000 = amount/1000;
    amount -= note1000 * 1000;
    }
    if(amount >= 500)
    {
    note500 = amount/500;
    amount -= note500 * 500;
    }
    if(amount >= 100)
    {
    note100 = amount/100;
    amount -= note100 * 100;
    }
    if(amount >= 50)
    {
    note50 = amount/50;
    amount -= note50 * 50;
    }
    if(amount >= 20)
    {
    note20 = amount/20;
    amount -= note20 * 20;
    }
    if(amount >= 10)
    {
    note10 = amount/10;
    amount -= note10 * 10;
    }
    if(amount >= 5)
    {
    coin5 = amount/5;
    amount -=coin5 * 5;
    }
    if(amount >= 2)
    {
    coin2 = amount/2;
    amount -=coin2 * 2;
    }
    if(amount >= 1)
    {
    coin1 = amount;
    }


    printf("Total number of notes = \n");


    textcolor(GREEN);
    cprintf("5000 = %ld\n", note5000);
    textcolor(MAGENTA);
    cprintf("1000 = %ld\n", note1000);
    textcolor(MAGENTA);
    cprintf("500  = %ld\n", note500);
    textcolor(MAGENTA);
    cprintf("100  = %ld\n", note100);
    textcolor(MAGENTA);
    cprintf("50  = %ld\n", note50);
    textcolor(MAGENTA);
    cprintf("20  = %ld\n", note20);
    textcolor(MAGENTA);
    cprintf("10  = %ld\n", note10);
    textcolor(MAGENTA);
    cprintf("5    = %ld\n", coin5);
    textcolor(MAGENTA);
    cprintf("2    = %ld\n", coin2);
    textcolor(MAGENTA);
    cprintf("1    = %ld\n", coin1);


    getch();


    return 0;
}

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Above is my code,I want this program to ask amount and then check the amount and ask in which denominations the money is required depending on the amount and I want to add font style please help me.

When you start putting numeric suffixes on variables, it's a sure sign you should be thinking about an array.

Code:

---

#include<stdio.h>

#define NUM_DENOMINATIONS 10

int main()
{
    long amount;
    long denominations[NUM_DENOMINATIONS] = {
      5000, 1000,
      500, 100,
      50, 20, 10,
      5, 2, 1
    };
    long change[NUM_DENOMINATIONS] = { 0 };

    printf("Enter the amount: ");
    scanf("%ld", &amount);

    for ( int i = 0 ; i < NUM_DENOMINATIONS ; i++ ) {
      if ( amount >= denominations[i] ) {
        change[i] = amount / denominations[i];
        amount -= change[i] * denominations[i];
      }
    }

    printf("Total number of notes = \n");
    for ( int i = 0 ; i < NUM_DENOMINATIONS ; i++ ) {
      printf("%ld = %ld\n", denominations[i], change[i] );
    }

    return 0;
}

---

> ask in which denominations the money is required
Like

Code:

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char required_denominations[100];
printf("Enter required denominations, eg 50,20,10\n");
scanf("%s",required_denominations);

---

You then parse the char array, and extract the denominations you want.
I suppose you could start with an empty denominations array (filled with zeros).

> depending on the amount
Like for example, they enter an amount of 55 and only allow denominations of 20,10.
Who gets to keep the 5 ?

> and I want to add font style please help me.
Yeah, consoles and terminals don't do fonts.

Forget about textcolor and any other eye candy until your program is finished and working as you want it.
Throwing in some decoration is very easy at the end, but a real PITA (and a time waster) to keep maintaining while trying to get the rest of the program working.

Change making is a difficult problem. It's usually easy to find a trivial solution (all units), and a better algorithm (take the highest note and subtract until you can do no more, then repeat with the next highest note) is also fairly easy. But you can do better.

What I suggest is that you start with the interface. You need to pass the amount of money, and the notes availbale in, and you need a list of notes out.

So I suggest

Code:

---

void makchange(long amount, const long *denominations, int Ndenominations, long *notesout)

---

You call it like this

Code:

---

long denominations[6] {50, 20, 10, 5, 2, 1}; // notes avialable
long amount = 210;
long notes[6]; // where we store the notes

makechange(amount, denominations, 6, notes);
for (i = 0; i < 6; i++)
{
    if (notes[i] > 0)
      printf("%ld note : %ld\n" denominations[i], notes[i]);
}

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