How to pass a structure member to a function?

Code:

---

struct msg_rsp
{
  int count;
  struct info *info_entry;
};

void func()
{
  struct msg_rsp *resp;
 
  for (int i = 0; i < resp->count;  i++)
    {
    // How to pass resp->info_entry here to the function func( ) & increment pointer?
      func (); 
    }

}

void func (struct info *entry)
{
  ..
  ..
}

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How to pass argument properly to func () and increment the pointer to next ?

You practically answered your own question:

Code:

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func(resp->info_entry);

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Ok. But how to increment pointer after calling function?

Quote:

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Originally Posted by krishnampkkm

But how to increment pointer after calling function?

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A direct answer to your question is extremely simple: given a pointer p, you can increment the pointer in any one of at least four ways:

Code:

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++p;
p++;
p += 1;
p = p + 1;

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But it doesn't sound like this is what you're looking for. Firstly, what pointer did you have in mind? You have the resp pointer and the resp->info_entry pointer, and it is not clear which you are referring to. Furthermore, it is not clear what "increment the pointer to next" means in this context. Is this supposed to be some kind of linked list or does the pointer in question point to an element within an array?

Maybe

Code:

---

  for (int i = 0; i < resp->count;  i++)
    {
    // How to pass resp->info_entry here to the function func( ) & increment pointer?
      func( &resp->info_entry[i] ); 
    }

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