passing struct containing char string into a function

I have a header file containing:

Code:

---

struct confTimer{
    char name[3];
    char direction[8];
    uint countValue;
};


uint run_timer(struct confTimer cT);

---

I have a function file containing:

Code:

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uint run_timer(struct confTimer cT){
    if (!strcmp(cT.name, "B0")) {

---

I have main (separate file) containing:

Code:

---

    struct confTimer radioT;




        radioT.name[3] = "B0";
        radioT.direction[8] = "up_down";
        radioT.countValue = 4455;
        run_timer(radioT);

---

I am never stepping into the function at the conditional if...What am I missing?
Thanks

You can not assign c-string in C!
You need to use strcpy or strncpy function to copy C-strings.

I suggest reading the warning you get while compiling!

Tim S.

Code:

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radioT.name[3] = "B0";

---

And, this is wrong even in C++!

In C++, this should work.

Code:

---

radioT.name = "B0";

---

Tim S.

You should've got warnings with that code. Don't ignore warnings.
You need to use strcpy to set the contents of a string.
And you should probably pass the struct by pointer.

Code:

---

#include <stdio.h>
#include <string.h>
 
typedef unsigned int uint;
 
struct confTimer{
    char name[3];
    char direction[8];
    uint countValue;
};
 
uint run_timer(struct confTimer *cT){
    if (!strcmp(cT->name, "B0")) {
        printf("%s, %d\n", cT->direction, cT->countValue);
    }
    return 0;
}
 
int main() {
    struct confTimer radioT;
    strcpy(radioT.name, "B0");
    strcpy(radioT.direction, "up_down");
    radioT.countValue = 4455;
    run_timer(&radioT);
    return 0;
}

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If you want to initialise, you can do so with an aggregate:

Code:

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struct confTimer radioT = {"B0", "up_down", 4455};

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