Function pointer issue

Hi, i have a problem with my code. Currently i am trying to learn function pointers and the best way is practicing but my little program don't work as it should. After i call (*execute) it does not show anything and i don't get what's wrong. execute is assgined to point to a function by pick_function. Maybe could someoane look on to my code:

Code:

---

#include <stdio.h>
#include <stdlib.h>


typedef void (*fptr)(void);


void func1(void)
{
    printf("\n\t\t Message 1\n\n");
}
void func2(void)
{
    printf("\n\t\t Message 2\n\n");
}
void func3(void)
{
    printf("\n\t\t Message 3\n\n");
}
void func4(void)
{
    printf("\n\t\t Message 4\n\n");
}




fptr pick_function(fptr array_of_fptr[])
{
    int insert;
    printf("\n\n\t\t Choose a message between 0-6 \n\n");


    do scanf("%d",&insert);
    while((insert<0)||(insert>3));


    switch (insert)
        {
        case 0:
            return array_of_fptr[0];
            break;
        case 1:
            return array_of_fptr[1];
            break;
        case 2:
            return array_of_fptr[2];
            break;
        case 3:
            return array_of_fptr[3];
            break;
        }
}




int main()
{


    fptr array_of_fp[4]={func1,func2,func3,func4},execute;
    execute=pick_function(array_of_fp);
    (*execute);


}

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Thanks in advance!

You need to call the function through the function pointer:

Code:

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(*execute)();

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It should also be possible to omit the explicit dereference as a form of syntactic sugar:

Code:

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execute();

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It worked. Thanks very much!!