Need help on exercise!

Hello to everyone. I am new to programming, recently started with some small exercises where i am supposed to have my user do this



* user to enter the number of digits
* user to enter the n-digit number
Note: The n-digit number is read in using a scanf statement and you are
not allowed to read in the n-digit number as individual digits or characters
* to seperate the digits from the n-digit number entered using repetition statements
(i.e. you should use while or for loop in your program)
* Hint: you can use a combination of integer division (/) and reminder operation (%).


* The final result is to display the individual digits with 3 spaces in
between the digits.
For e.g., if n is 5 and the number entered is 54321, the printout will be
5 4 3 2 1

my code is roughly there, i can produce all the outputs except for a few exception. Every input that has a '0' at the end of the number will have the 0 omitted, for e.g. 10 will have an output of 1, same as with 100, 1000 so forth. How can i fix this? Any help would be appreciated :devil:

Code:

---

#include <stdio.h>
#include <math.h>


int main()


{


        int testInteger;
        int x;
        int digit;
        int counter;
       
       
                printf("Please enter the number of digit(s)\n");
                scanf("%d",&digit);
       
        if (digit < 0 && digit > 9) {                                               
                       
                printf("Invalid digit, please try a new value\n");
                scanf("%d",&digit);
               
                }       
               
                       
        else{
       
        counter = pow(10,digit -1);               
       
                printf("Enter an integer\n");
                scanf("%d", &testInteger);
                printf("Number = %d\n", testInteger);
       
       
       
        while(testInteger>0 )
        {
               
                x = testInteger/counter;                       
                printf("%d  ",x);               
                testInteger = testInteger%counter; 
                counter = counter/10;       
        }
       
       
        }
        }

---

Perhaps:

Code:

---

#include <stdio.h>
 
typedef unsigned long long ull;
 
int main()
{
    ull n;
    scanf("%llu", &n);
 
    ull mag = 1;
    for (ull m = n; (m /= 10) != 0; mag *= 10)
        ;
 
    for ( ; mag > 1; mag /= 10)
        printf("%llu  ", n / mag % 10);
    printf("%llu\n", n % 10);
 
    return 0;
}

---

Or maybe:

Code:

---

#include <stdio.h>
 
typedef unsigned long long ull;
 
void print_digits(ull n)
{
    if (n > 9) print_digits(n / 10);
    printf("%llu  ", n % 10);
}
 
int main()
{
    ull n;
    scanf("%llu", &n);
    print_digits(n);
    putchar('\n');
    return 0;
}

---

Hey johnc,

I thank you for your work! Wow that is some pretty complicated stuff, it may be a tad too difficult for me to comprehend now, i was thinking of perhaps if i could add an if statement in the while loop to make the 0 appear as it seems as though the missing zero comes from a division by zero error but that i'm not really sure how to execute the steps. I'll keep your solution for future references though! Thanks

Quote:

---

Originally Posted by john.c

Perhaps:

Code:

---

#include <stdio.h>
 
typedef unsigned long long ull;
 
int main()
{
    ull n;
    scanf("%llu", &n);
 
    ull mag = 1;
    for (ull m = n; (m /= 10) != 0; mag *= 10)
        ;
 
    for ( ; mag > 1; mag /= 10)
        printf("%llu  ", n / mag % 10);
    printf("%llu\n", n % 10);
 
    return 0;
}

---

Or maybe:

Code:

---

#include <stdio.h>
 
typedef unsigned long long ull;
 
void print_digits(ull n)
{
    if (n > 9) print_digits(n / 10);
    printf("%llu  ", n % 10);
}
 
int main()
{
    ull n;
    scanf("%llu", &n);
    print_digits(n);
    putchar('\n');
    return 0;
}

---

---

It really isn't very complicated.
Asking the user for the number of digits in the input number is not a good solution since the program can calculate that (which is what mag is for).
Here it is with just ints if that makes it look easier:

Code:

---

#include <stdio.h>
 
int main()
{
    int n;
    scanf("%d", &n);
 
    // determine the magnitude
    int mag = 1;
    for (int m = n; (m /= 10) != 0; mag *= 10)
        ;
 
    // strip off the digits from high-order to low-order
    for ( ; mag > 1; mag /= 10)
        printf("%d  ", n / mag % 10);
    printf("%d\n", n % 10);
 
    return 0;
}

---

Using unsigned long long instead of int allows longer numbers.
Max 32-bit signed int is 2147483648.Max 64-bit unsigned long long is 18446744073709551616.