How to pass an array by value in C

I am passing the one element while I want to pass all the elements without a pointer. How to pass an array by value in C

Code:

---

#include<stdio.h>

void Display(int a);


int main()
{
    int Arra[] = { 2, 3, 4 };
    Display(Arra[1]);        //Passing array element  only.
    return 0;
}


void Display(int a)
{
    printf("%d", a);
}

---

You could wrap the array in a struct... but then you would want to use a pointer because the struct object would be expensive to copy. So don't bother: use a pointer.

Quote:

---

Originally Posted by laserlight

You could wrap the array in a struct... but then you would want to use a pointer because the struct object would be expensive to copy. So don't bother: use a pointer.

---

Does this mean that we cannot pass the array by its value?

If we have to pass Array, then we have to pass its location so we have to use the pointer that would pass location of array element

Yes, an array will always be converted to a pointer to its first element when passed as an argument to a function.

Why do you feel you need to pass the array by value?

If you must, put the array in a struct, since you can pass these by value.
But you need to understand that 'by value' means 'make a copy', which could be expensive for large arrays.