User-defined types to built in types

Hey!

Is it possible to have an user-defined type behave exactly like another type, the other type being a built-in type? Every reference to the user-defined type in code is to be treated as a different type (in my case, a built-in type).

So, if I have:

Code:

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Foo <T>

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it should behave exactly like T does as in the default behaviour in every statement of code involving type Foo<T> is treated as T. Reason for this is that if I provide additional functionality to class Foo, I can have default behaviour of T along with that additional functionality.

The normal way is to simply ditch Foo and provide additional functionality for the built-in type by means of functions.