Pass bitset pattern to constructor

Hello,

How can I pass an expression similar to the one I commented out (instead of the binary representation) to the constructor? I would like to make the constructor argument more readable.

Code:

---

#include <iostream>
#include <bitset>

struct Person
{
        const char* Name;
        int Age;
        std::bitset<4> State{};
        Person(const char* name, int age, std::bitset<4> state) : Name(name), Age(age), State(state) {}
};

int main()
{
        std::bitset<4> isBad{ 0b0001 };
        std::bitset<4> isSad{ 0b0010 };
        std::bitset<4> isMad{ 0b0100 };
        std::bitset<4> isFat{ 0b1000 };

        Person me("Joe", 25, std::bitset<4>{ 0b0101 });
        //me.State |= isBad | isMad;
       
        if((me.State & isBad).any()) std::cout << "Bad" << '\n';
        if((me.State & isMad).any()) std::cout << "Mad" << '\n';
}

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This works for me (in C++14 so that the binary literals are legal) :

Code:

---

#include <iostream>
#include <bitset>


using State = std::bitset<4>;
 
struct Person {
    static const State isBad, isSad, isMad, isFat;


    const char* name;
    int age;
    State state;


    Person(const char* name, int age, State state)
        : name(name), age(age), state(state) {}


    void ShowState() {
        if((state & isBad).any()) std::cout << "Bad\n";
        if((state & isSad).any()) std::cout << "Sad\n";
        if((state & isMad).any()) std::cout << "Mad\n";
        if((state & isFat).any()) std::cout << "Fat\n";
    }
};


const State Person::isBad{ 0b0001 },
            Person::isSad{ 0b0010 },
            Person::isMad{ 0b0100 },
            Person::isFat{ 0b1000 };


int main() {
    Person me("Joe", 25, State{ Person::isBad | Person::isMad });
    me.ShowState();
}

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Wow, thank you for fixing the code, I really appreciate it!