what happen during the execution of code

I need help to understand program

Code:

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#include<stdio.h>

void function (void);


int main (void)
{
  int a = 5;


  printf ( "\n a : %d", a); 
 
  function();
   
    return 0;
}


void function (void)


{
        int b = 15;
        b++;
        printf ("\n b : %d", b); 
}

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a : 5
b : 16

There are two variables a and b

I do not understand what happen during the execution of code

How long variable a will exit ?
When we call function how long variable b will exit ?
Where does it will store stack or heap ?

any help would be appreciated

Quote:

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How long variable a will exit ?

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Code:

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int main (void)
{
    int a = 5; // 'a' starts existing here
    printf ( "\n a : %d", a); 
   
    function(); // 'b' starts existing and stops existing here
     
    return 0; // 'a' stops existing here
}

void function (void)
{
    int b = 15; // 'b' starts existing here
    b++;
    printf ("\n b : %d", b);
} // 'b' stops existing here

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Quote:

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Where does it will store stack or heap ?

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All on the stack.

p.s. please format your code properly next time, i.e. with consistent indentation and no large gaps.

Quote:

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Originally Posted by Guest

All on the stack.

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Depends on the compiler optimization. Could be on registers.