Program doesn't print all letters entered by user

Program doesn't print all letters entered by user

Code:

---

#include<stdio.h>int main (void)
{
        int i;
        char array[15];
        int size;
       
        printf("promote user to enter size off array  :" );
        scanf("%d",&size);
       
        for(i=0; i<size; i++)
        {
                printf("print array element : ", array[i]);
                scanf("%c",&array[i]);
        }
   
    return 0;


}

---

promote user to enter size off array :5
print array element : print array element : a
print array element : print array element : b
print array element :

Why does it only print two letters only ?

Perhaps you should print the variable after you have the user enter the value?

Nothing change happen it gives a same result

Code:

---

#include<stdio.h>

int main (void)
{
    int i;
    char array[15];
    int size;
   
    printf("promote user to enter size off array  :" );
    scanf("%d",&size);
   
    for(i=0; i<size; i++)
    {
        scanf("%c",&array[i]);
                printf("print array element : ", array[i]);
       
    }
   
    return 0;
 
 
}

---

promote user to enter size off array :5
print array element : a
print array element : print array element : b
print array element : print array element :

The problem is that 1. scanf() leaves the end of line character in the input buffer and 2. when using the "%c" format character leading whitespace is not skipped.

To fix the problem you can either enter all the characters without pressing the enter key, "abcde", or force the "%c" format specifier to skip leading whitespace by using a space before the specifier " %c".

> scanf("%c",&array[i]);
If you want to read the next printable character (ignoring all white space), then add a leading space to your scanf format string.
scanf(" %c",&array[i]);

Quote:

---

Originally Posted by Salem

> scanf("%c",&array[i]);
If you want to read the next printable character (ignoring all white space), then add a leading space to your scanf format string.
scanf(" %c",&array[i]);

---

Thanks salem I have another question where i am struggling




I want to store multiple strings entered by user

Code:

---

#include<stdio.h>

int main(void)


{
        unsigned int i;
       
        char name[5][5]= {"bil","del","sen", "jan","gan"};
       
        for(i=0; i <5;i++)
        {
                printf("candidate name = %s \n",name[i]);
        }
       
       
        return 0;
       
}

---

candidate name = bil
candidate name = del
candidate name = sen
candidate name = jan
candidate name = gan

How to store multiple strings entered by user?

Pretty much the same way

char names[5][10];

Then a loop of
scanf( "%s",names[i] );