Arguments of lambda functions need to be local?

Hello,

I just wanted to check on this. I have the statement below inside a function (method of Player) that checks that all weapons in the Loadout vector has the same scale as the Player who carries them:

Code:

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int playerscale = PlayerScale;
bool IncorrectScale = any_of(Loadout.begin(), Loadout.end(), [&playerscale](auto& weapon) { return weapon->WeaponScale != playerscale; });

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My question is: Does PlayerScale always need to be converted to local before being used this way? Thank you for your time!

You can capture (by value) the pointer to your class object:

Code:

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bool IncorrectScale = any_of(Loadout.begin(), Loadout.end(), [this](auto& weapon) { return weapon->WeaponScale != PlayerScale; });

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Quote:

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Originally Posted by Guest

You can capture (by value) the pointer to your class object:

Code:

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bool IncorrectScale = any_of(Loadout.begin(), Loadout.end(), [this](auto& weapon) { return weapon->WeaponScale != PlayerScale; });

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Ah.. nice! Thx again