Hybrid Password

Hello guys password in my code must escape the hacker.I tried to do something with swap but I couldn't make the loop.Could you help please?

Code:

---

#include <stdio.h>


void swap(int *value,int*Hybridized_Password){
        int swap_operand =*value;
        *value =*Hybridized_Password;
        *Hybridized_Password = swap_operand;
}
int main()
{
        int a=1111
        int password[4] ={9999};
        printf("\nBefore Swapping Hybridization:a=%d & password[0]=%d\n",a,password[0]);
       
        swap(%a,&password[0]); // a and default password go swap function
       
printf("\nAfter Swapping Hybridization:a=%d &password[0]=%d\n",a, password[0]);
}

---

How does it not work, and what does this "hybrid password" have to do with anything?

This is the only hybridization part.I have to set loop of it but I could not

the letters will escape to the farthest values ​​with ascii code.
Example my password abcd.For example my password is ABCD. if the hacker approaches my password, thanks to ascii code will be missed Will be 9876

So... Just to clarify...

A - > 9
B - > 8
C - > 7
D - > 6
E - > 5?
...
J - > ?

Cross-posted here -> Hybrid password - C++ Forum

I can't be the only one scratching my head on this one.

Can you explain what you mean by each the following statements in your description?

• "the letters will escape": how does a letter "escape"? What is it escaping?
• "to the farthest values with ascii code": what is the "farthest value", and how are you expecting to use ASCII to achieve this?
• "if the hacker approaches my password": how does a hacker "approach" your password? What does that even mean?
• "thanks to ascii code will be missed": how will the password be "missed"?
• How do you get "9876" from "ABCD" (or is it "abcd")?