struggeling with an if statment clause

ill try to explain the clauses for it to be true

x can be 1 or -1 but has to be one of those 2
y has to be 1 if king is false or y can be 1 or -1 if king is true

Code:

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    x=1 | x=-1 | y=1 | y=-1 | king true | king false | desired result
    ____|______|_____|______|___________|____________|_________________
      0 |  1  |  0  |  1  |    0      |    1      |  0
      0 |  1  |  1  |  0  |    0      |    1      |  1   
      1 |  0  |  0  |  1  |    0      |    1      |  0
      1 |  0  |  1  |  0  |    0      |    1      |  1
      0 |  1  |  0  |  1  |    1      |    0      |  1
      0 |  1  |  1  |  0  |    1      |    0      |  1   
      1 |  0  |  0  |  1  |    1      |    0      |  1
      1 |  0  |  1  |  0  |    1      |    0      |  1

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hopefully the truth table will come out ok
coop

i have tried

Code:

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if (((x == -1 || x == 1) && (y == 1 || y ==-1) && king == true) || ((x == -1 || x== 1) && y == 1))

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but it always was true regardless of y and the king
coop

I would focus on the two result=0 cases.

This is true, regardless of the state of x/y
if ( king == 1 ) result = 1;

Also
if ( !king && ( (x==-1 && y==-1) || (x == 1 && y== -1) ) ) result = false;

This is not a truth map.... I'm assuming (x==-1) means truth and (y==-1) means truth, otherwise, false. You'll end up with this table:

Code:

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x=-1 | y=-1 | king true | result
 (A) |  (B) |    (C)    |  (S)
_____|______|___________|_________________
 0  |  0  |    0      |    1 = ~A~B~C
 0  |  0  |    1      |    1 = ~A~BC
 0  |  1  |    0      |    0
 0  |  1  |    1      |    1 = ~ABC
 1  |  0  |    0      |    1 = A~B~C
 1  |  0  |    1      |    1 = A~BC
 1  |  1  |    0      |    0
 1  |  1  |    1      |    1 = ABC

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Using a kmap (as I showed before), you can simplify this with:
Attachment 15757
Which will result in S=~B || C. Your condition should be:

Code:

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if (y==1 || king ) ...

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trouble is i havent done demorgans and kaunaugh for about 25 years and then it confused me how you decided which square was A and which was ~A for example however i take your point all i need is the statment
if ((king == true || y == 1) && (x == -1 || x == 1)) as although x doesn't infulence the outcome i need to test that it is either 1 or -1

coop

Quote:

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Originally Posted by cooper1200

trouble is i havent done demorgans and kaunaugh for about 25 years and then it confused me how you decided which square was A and which was ~A

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It is in the FIRST sentence on my text!

Quote:

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Originally Posted by cooper1200

for example however i take your point all i need is the statment
if ((king == true || y == 1) && (x == -1 || x == 1)) as although x doesn't infulence the outcome i need to test that it is either 1 or -1

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Then, again, your truth table is wrong... There are 5 vars, not 6, unless "king" can be different from true or false.
With 5 vars you should have a truth table with 32 entries... with 6, 64...