Errors in my C program

Code:

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void printListReversed(node *list) {113
114
115
116  if (list!=NULL) return;
117
118  double x,y;
119  list = list->next;
120
121  do
122    {
123      printf("%lf \t %lf",x,y);
124      list= list->prev;
125    } while (list->next !=NULL){
126
127
128
129    /* list = list->next; list->next */
130  }
131
132
133 }

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Code:

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~/> icc -ansi -Wall -c -o list.o list.c

list.c(125): error: expected a ";"
      } while (list->next !=NULL){
                                  ^
list.c(133): warning #12: parsing restarts here after previous syntax error
  }
  ^


compilation aborted for list.c (code 2)

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Hello, I am having errors in my code and I can't seem to figure out.
anyone can help, please.

Thanks in advance

That opening brace should have been a semi-colon as you're ending the do while loop.

Quote:

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Originally Posted by laserlight

That opening brace should have been a semi-colon as you're ending the do while loop.

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Code:

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  do   
122          ;
123      printf("%lf \t %lf",x,y);
124      list= list->prev;
125    } while (list->next !=NULL){
126
127
128
129    /* list = list->next; list->next */
130  }
131
132
133 }

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You can do either or, but not both at the same time:

Code:

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do {
    ...
} while (...);

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Code:

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while (...) {
    ...
}

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Quote:

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Originally Posted by erald23

Code:

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void printListReversed(node *list) {113
114
115
116  if (list!=NULL) return;
117

---

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maybe after all of them mistakes pointed out , I am putting your logic to question. your first check is for if list Not Null then return , causing it to leave your function,

then here,

Quote:

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Originally Posted by erald23

118 double x,y;
119 list = list->next;
120
121 do
122 {
123 printf("%lf \t %lf",x,y);
124 list= list->prev;
125 } while (list->next !=NULL){
126
127
128
129 /* list = list->next; list->next */
130 }
131
132
133 }

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your second operation on your list is to iterate through your list until it is NULL.

do you see the conflict within your function?

Quote:

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Originally Posted by erald23

[CODE]void printListReversed(node *list) {113
114
115
116 if (list!=NULL) return;
117
118

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This line doesn't make sense as far as I can see: Following lines of code will only be executed if list is a NULL-pointer. but if list is NULL, there won't be a
list->next etc.