Problem with the Result of the code

Code:

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#include <stdio.h>
#include <math.h>
int main()
{
    int i, k;
    for(i = 0; i < 6; i++){
        k = pow(10, i);
        printf("%d\t", k);
    }
    return 0;
}

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Getting this result

Code:

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1    10    99    1000    9999    100000

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But i want

Code:

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1    10    100    1000    10000    100000

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where is my bug??

pow returns a floating point value which will not be exact. In converting it to an integer, the decimals are just thrown away, even if they are .99999
So you probably want to round up the result by adding 0.5.

Code:

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k = int(pow(10, i) + 0.5);  // added .5 to round up (and made cast to int explicit so it's more obvious)

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If you really just want powers of 10, pow may not be the best choice. It's probably better to start an integer at 1 and repeatedly multiply it by 10. But beware of going beyond the limit of the type.

Consider this:

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int i;
    int k=1;
   
    for(i=1; i<7; i++)
    {
        printf("%d\n",k);
        k *= 10;
    }

    return EXIT_SUCCESS;
}

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