im a newbie at c please help.

Please could someone explain to me why this isnt working, also is there a way for me to not have to type in all the variables when i want multiple typed like i have done here. thanks.

Code:

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#include <stdio.h>
#include <stdlib.h>
int main(){
 
 int grade[10][0];
 
 grade[0][0]=0;
 grade[1][0]=0;
 grade[2][0]=0;
 grade[3][0]=0;
 grade[4][0]=0;
 grade[5][0]=0;
 grade[6][0]=0;
 grade[7][0]=0;
 grade[8][0]=0;
 grade[9][0]=0;
 printf("Please enter your students exam mark seperated by a space \n");
 fflush(stdin);
 scanf("%d %d %d %d %d %d %d %d %d %d \n", grade[1][0], grade[2][0], grade[3][0],grade[4][0], grade[5][0], grade[6][0], grade[7][0], grade[8][0], grade[9][0], grade[0][0]);
 float totgrade= grade[1][0]+grade[2][0]+grade[3][0]+grade[4][0]+grade[5][0]+grade[6][0]+grade[7][0]+grade[8][0]+grade[9][0]+grade[10][0];
 
 printf("The total mark is: %f \n", totgrade);
 
 float avgrade=totgrade/10;
 printf("The average mark = %.1f", avgrade);
 
 system("pause");
 return 0;
}

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This doesn't make sense and should have resulted in a compile error, or at least a warning:

Code:

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int grade[10][0];

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It looks like you want to read in the grades of ten students, one grade per student, so you should have written:

Code:

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int grade[10] = {0};

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The zero initialisation means that you don't have to manually set the initial value of all the elements to zero.

This is non-standard and you should remove it since you don't need it here:

Code:

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fflush(stdin);

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Next, for the scanf, while you could have a format string consisting of ten format specifiers, you may find it easier to use a loop that reads one grade per iteration. Note that the elements of the grade array start from grade[0] and ends at grade[9], not grade[10].

Oh, and remember to indent your code so as to make it more readable.

Code:

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#include <stdio.h>
#include <stdlib.h>
int main(){
 
 int grade[10]={0};
  printf("Please enter your students exam mark seperated by a space \n");
  scanf("%d %d %d %d %d %d %d %d %d %d \n", grade[1], grade[2], grade[3],grade[4], grade[5], grade[6], grade[7], grade[8], grade[9], grade[0]);
  printf("%d", grade[4]);
 
 float totgrade= grade[1]+grade[2]+grade[3]+grade[4]+grade[5]+grade[6]+grade[7]+grade[8]+grade[9]+grade[0];
 
  printf("The total mark is: %f \n", totgrade);
 
 float avgrade=totgrade/10;
  printf("The average mark = %.1f", avgrade);
 
 system("pause");
 return 0;
}

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Every grade in your scanf line needs to be &grade[n]

A better compiler will tell you such things.

Code:

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$ gcc -Wall foo.c
foo.c: In function ‘main’:
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 2 has type ‘int’ [-Wformat=]
  scanf("%d %d %d %d %d %d %d %d %d %d \n", grade[1], grade[2], grade[3],grade[4], grade[5], grade[6], grade[7], grade[8], grade[9], grade[0]);
        ^
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 3 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 4 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 5 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 6 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 7 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 8 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 9 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 10 has type ‘int’ [-Wformat=]
foo.c:7:9: warning: format ‘%d’ expects argument of type ‘int *’, but argument 11 has type ‘int’ [-Wformat=]

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