Passing value of parameters in main funtion

I wrote my own program to understand the basic of function calling and passing parameters

Code:

---

#include<stdio.h>void loop (unsigned int i)
{
 for (i = 0; i < 10; i++)
 {
 }
}
int main(void)
{ 
    loop (6);
    return 0;
}

---

I think loop run 10 times in function but if I pass value 6 in main function then it will run only 6 times

Your function ignores the parameter, and just loops 10 times anyway.

Give your parameter a decent name.

Quote:

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Originally Posted by Salem

Your function ignores the parameter, and just loops 10 times anyway.

Give your parameter a decent name.

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I didn't get your point. Why does it ignores the parameter as per my knowledge when main function call to delay function then loop will run only 6 times. I think if I pass the value 2 in main function then loop will run 2 times. What's wrong in program ?

Quote:

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What's wrong in program ?

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Look at your function closely. Do you ever use the value you passed into your function?

Quote:

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Originally Posted by jimblumberg

Look at your function closely. Do you ever use the value you passed into your function?

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what is meaning of this > Do you ever use the value you passed into your function?

if possible can you give example

I wrote this program for understanding calling function

Code:

---

#include<stdio.h>
void loop (void)
{
 unsigned int count;
 for (count = 0; count < 10; count++)
 {
  printf("Number :  %d \n", count);
 }
}
int main(void)
{ 
    loop();
    return 0;
}

---

Number : 0
Number : 1
Number : 2
Number : 3
Number : 4
Number : 5
Number : 6
Number : 7
Number : 8
Number : 9

And now imagine if you changed the function to:

Code:

---

void loop (unsigned int count)
{
    // unsigned int count;  <-- no longer used
    for (count = 0; count < 10; count++) {
        ...
    }
}

---

What do you think happens? Consider that your function knew how to loop without being passed an argument.

Does it make any sense

Code:

---

#include<stdio.h>
void loop (unsigned int number)
{
 unsigned int count;
 for (count = 0; count < number; count++)
 {
  printf(" count : %d \n",count);
 
 }
}
int main (void)
{
  loop(6);
 
  return 0;
}

---

count : 0
count : 1
count : 2
count : 3
count : 4
count : 5

I think I can pass any value

Code:

---

#include<stdio.h>
void loop (unsigned int number)
{
 unsigned int count;
 for (count = 0; count < number; count++)
 {
  printf(" count : %d \n",count);
 
 }
}
int main (void)
{
  loop(6);
  loop(4);
  loop(2);
  return 0;
}

---

count : 0
count : 1
count : 2
count : 3
count : 4
count : 5

count : 0
count : 1
count : 2
count : 3

count : 0
count : 1

I'm please you got it right eventually.