Print the array element error in program

I was trying to write program where I want to print array element

Code:

---

#include <stdio.h>
int main (void)
{
 unsigned i, array[5] = {1,2,3,4,5};
 
 for (i = 0, i < 5; i++)
 {
  printf(" Print array element : %d  \n", array[5])
 }

 
 return 0;
}

---

compiler show error

hello.c:8:24: error: expected ';' before ')' token
for (i = 0, i < 5; i++)
^
hello.c:11:2: error: expected ';' before '}' token
}

if I use array [5]
then
Print element of array : 0
Print element of array : 1
Print element of array : 2
Print element of array : 3
Print element of array : 4

I don't understand why there is array [5] only ?

Your program has syntax errors, and your compiler is trying to tell you about the right syntax it was expecting. Look between your for loop parentheses and make sure it is written with semi-colons separating the three terms. Make sure that all your lines end with a semi-colon.

Edited to add: Changing array[i] to array[5] does not address the syntax errors that are still in this version of the program. Perhaps you changed other things, but no, doing that did not address the problems. Look at my compile of your latest code for proof of that:

Code:

---

C:\Users\jk\Desktop>gcc -c vead.c
vead.c: In function 'main':
vead.c:6:24: error: expected ';' before ')' token
  for (i = 0, i < 5; i++)
                        ^
vead.c:9:2: error: expected ';' before '}' token
  }
  ^

C:\Users\jk\Desktop>more vead.c
#include <stdio.h>
int main (void)
{
 unsigned i, array[5] = {1,2,3,4,5};

 for (i = 0, i < 5; i++)
 {
  printf(" Print array element : %d  \n", array[5])
 }


 return 0;
}

---

With errors like these, no executable is made, so there is nothing to run.

I am not sure if I totally understand your question, but you have tons of error as whiteflags said.

Here is a working code:

Code:

---

#include <stdio.h>
int main (void)
{
    unsigned i, array[5] = {1,2,3,4,5};


    for (i = 0, i < 5; i++)
    {
        printf(" Print array element : %d  \n", array[i])
    }


    return 0;
}

---

Quote:

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Here is a working code:

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Yea, not even close.

Quote:

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Originally Posted by jimblumberg

Yea, not even close.

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It's not a bad effort (LOL!)