I want to know is it usually displayed(Error0)or it is my code which may be defected!

Here is my code

Code:

---


//Program in C
/* Using strchr() & strcmp()
* function(s) to do some conditional(s) */


#include <string.h>
#include <stdio.h>
#include <conio.h>
main() {
clrscr();


char name[20];
char *ptr;
/* Taking an animal name from user */


printf("Hello! Which animal does meow sound? ");
fgets(name, 20, stdin);


if ((ptr = strchr(name, '\n'))) {
    //Replacing newline with NULL
    *ptr = '\0';
}


//Performing check on user input
char match[4] = "Cat";
if (strcmp(name, match) == 0) {
    printf("Bravo! You are correct.");
    getch();
} else {
    perror("Sorry! That was Cat.");
    getch();
}


return(0);


}

---

Prompt: Hello! Which animal does meow sound?
Input: Doggy
Output: Sorry! That was Cat.: Error 0

Why is Error 0 being displayed?
Please give me explanation.

Although you haven't bothered to give us any information about what system/compiler/IDE you're using, I assume that you're running your code from an IDE and it's simply telling you the return code of the program. Since you're returning 0 from main, it says Error 0. Try returning 1 from main and see if it says Error 1. (Remember to change it back to 0, though.)

perror shows value of errno. Since no error actually occurred - errno is 0. This is what is being printed

Quote:

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Originally Posted by vart

perror shows value of errno. Since no error actually occurred - errno is 0. This is what is being printed

---

I doubt it has anything to do with errno. That would be strange indeed.

Quote:

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Originally Posted by algorism

I doubt it has anything to do with errno. That would be strange indeed.

---

What would be strange?

Code:

---

//Program in C
/* Using strchr() & strcmp()
* function(s) to do some conditional(s) */
 
 
#include <string.h>
#include <stdio.h>

int main() {
 
 
char name[20];
char *ptr;
/* Taking an animal name from user */
 
 
printf("Hello! Which animal does meow sound? ");
fgets(name, 20, stdin);
 
 
if ((ptr = strchr(name, '\n'))) {
    //Replacing newline with NULL
    *ptr = '\0';
}
 
 
//Performing check on user input
char match[4] = "Cat";
if (strcmp(name, match) == 0) {
    printf("Bravo! You are correct.");
    getchar();
} else {
    perror("Sorry! That was Cat.");
    getchar();
}
 
 
return(0);
 
 
}

---

This is compiled by gcc 5.4 on Ubuntu and run from terminal without any IDE

Code:

---

$ ./test
Hello! Which animal does meow sound? as
Sorry! That was Cat.: Success

---

So instead of Error 0 it prints Success

I'm blind.
You're right.

Thanks everyone! For helping me out. Actually for me replacing perror() with printf() did the job & also changing main() function's return value from 0 to 1 does the same.

I was totally mistaken about the return value of main. It had nothing to do with it. I didn't notice that you were using perror where you should have just used printf.

You should never use perror unless you have already determined that an error has occurred. Library functions indicate that an error has occurred by a special return value (e.g., fopen returns NULL if an error occurs). strcmp doesn't have an error return value, so it never makes sense to call perror after a strcmp call.

Here's an example of using perror properly. Notice that we only call it after we know an error has occurred.

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main() {
    FILE *f = fopen("this_file_does_not_exist", "r");
    if (f == NULL) {
        perror("fopen");
        exit(EXIT_FAILURE);
    }
    printf("The file opened somehow!\n");
    fclose(f);
    return 0;
}

---

Yeah, Thaks man.
It all makes sense now.