question about basic programming

when running the following code, why do I get two different memory addresses?

Code:

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#include <stdio.h>


int main(void){


    int  short signed number=-3;
    int short signed *pointer=&number;
    printf("the value of number is %d",number);
    printf("\n it's address in memory is %p",pointer);
    printf("\n it's address in memory is %d",pointer);




    return 0;
}

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The pedantically correct way to do this is with:

Code:

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printf("\n it's address in memory is %p", (void*)pointer);

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Though you probably can get away without the cast to void*.

Anyway, glossing over the undefined behaviour, you probably got the same address printed, just that they look different, kind of how "one hundred" and 100 (in base ten) are the same number but look rather different.