Getting current user username

Hello,

I tried the code as follows:

Code:

---

 
#include <windows.h>
#include <stdio.h>
#include <Lmcons.h>
#include <string>
#include <iostream>
int main()
{
 char username[UNLEN +1];
    DWORD username_len = UNLEN + 1;
    GetUserName((LPWSTR)username, &username_len);
    for each(auto test in username)
    {
        cout << test ;
    }
}

---

Which shows me that I indeed have chars inside username.
Now I try to do the following as described here on the answer also but it doesn't work.

The problem by the compiler is on that line and specifically on variable username:

Code:

---

GetUserName(username, &username_len);

---

Error says: Argument of type "Char*" is incompatible with parameter of type LPWSTR.
So I change my code to this:

Code:

---

char username[UNLEN + 1];
        DWORD username_len = UNLEN + 1;
        GetUserName((LPWSTR)username, &username_len);

---

And when I print it, I only get the first letter. Why?

Thanks in advance!

"LPWSTR" is basically "wchar_t*". "Char*" is, well, "char*"... Do you see why casting it to another pointer type doesn't work?

Well I tried this one as well:

Code:

---

    wchar_t username[UNLEN +1];
    DWORD username_len = UNLEN + 1;
    GetUserName(username, &username_len);
    cout << username<<"\n";

---

Still isn't working..

Anyway, wcout fixed it

Code:

---

    wchar_t username[UNLEN +1];
    DWORD username_len = UNLEN + 1;
    GetUserName(username, &username_len);
    wcout << username <<"\n";

---

Thanks

You probably have unicode selected in your project settings. But that's a good thing, since otherwise it won't handle non-US characters properly. That's why it wants to use wchar_t instead of char. Most Win32 API functions have two versions: one that takes char* and one that takes wchar_t*. By default, the compiler selects the unicode versions and they want wchar_t*.