memset vs normal assignment

Hi!

I'm working with Microchips USB framework on a PIC18F4550 and I'm pretty new to C. The goal is to understand how it and the PIC works.

Compiler = XC8

After reading some documentation about memset I'm confused with these two lines.

Code:

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UEP0 = 0;

memset((void*)&UEP1, 0x00, 0x01);

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The first line I understand clears the UEP0 register and from what I understand the second line does the same but for the UEP1 register, or am I wrong?

If I'm not wrong, what is the difference?? Why not just use

Code:

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UEP0 = 0;
UEP1 = 0;

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//R

It really depends on what UEP1 is.

Assignment will always make it zero regardless of how large the data type is.

memset as shown will only ever set the low byte to zero.

Quote:

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Originally Posted by Salem

It really depends on what UEP1 is.

Assignment will always make it zero regardless of how large the data type is.

memset as shown will only ever set the low byte to zero.

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UEP1 is a one byte register.
So in that case, is there a difference or is it the same?

Quote:

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Originally Posted by redsmolf

UEP1 is a one byte register.
So in that case, is there a difference or is it the same?

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When using memset for explicitly just one byte, the difference is that using a plain old assignment statement is both shorter to write and likely faster to execute.