fputc problem

Greetings. I wrote next program:

Code:

---

#include <stdio.h>

int main(int argc, char *argv[])
{

    FILE *fp, *fp2;
    int c;

    if(argc!=3) {
    printf("Usage:program infile outfile\n");
    return 0;}

    else
    fp=fopen(argv[1],"r");
    if(fp==NULL)
        {printf("Error: problem with opening %s\n",argv[1]);
        return 0;}

    fp2=fopen(argv[2],"w");
    if(fp==NULL)
        {printf("Error: problem with opening %s\n",argv[2]);
        return 0;}

    while(c=fgetc(fp)!=EOF)
    {
    fputc(c,fp2);
    }

    printf("Done.\n");
    fclose(fp);
    fclose(fp2);
   
    return 0;
    }

---

File _first_: "Hello, try to copy this"

After running program file _second_ looks like this:








































































































































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Help plz.

This:

Code:

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while(c=fgetc(fp)!=EOF)

---

Is equivalent to:

Code:

---

while(c=(fgetc(fp)!=EOF))

---

“c” is being set to either 0 or 1. You want:

Code:

---

while((c=fgetc(fp))!=EOF)

---

Thanks a lot, man! It really helps me!