char * problem

Here is the code:

char *tempName;

cout<<"Enter the name you wish to compare: ";
cin>>tempName;

but I am getting some sort of memory error, how do you read directly into the character pointer???

Pointer variables hold addresses, they cant hold characters. You have to dereferecne the pointer. Your pointer is only a pointer to a chacter too...it needs to point to an array, and you need to allocate space either on the stack or heap for it...id show you but im sure somone else will and im too hung over...

Code:

---

#include <iostream.h>

int main (void)
{
        char TempChar[55];
        char *pTempChar = &TempChar[0]; //Dereference

        cout<<"Enter the name you wish to compare: ";
        cin>>pTempChar;
        cout<<pTempChar<<'\n';

    return 0;
}

---

char * pTemp = new char[40];
cout << "enter name to be used in program";
cin >> pTemp;

If you use that solution you need to make sure you use delete when you are done with the char

or even better

Code:

---




  main()
  {
    char * pTemp = new char[40];
cout << "enter name to be used in program";
cin.getline(pTemp,40);
  cout<<pTemp;

    delete pTemp;

  system("pause");
  return 0;
  }

---

Shouldnt that be delete[]?
I dunno since its a pointer....

yup, should be delete [] pTemp. If you use [] after new you use [] after delete.

yes i thought i had missed something huge in that code

***No meaning with subjetc****


just glad to see someone who voted for Nader!!!


Barjor!

who's nader?

@Barjor:
char *pTempChar = &TempChar[0]; //Dereference

TempChar is already a adress, so you only need:
char *pTempChar=TempChar;