Basic prog help- passing parameters

I'm writing a function that takes a type double array[2][5] and stores the values in another double array, then print both out. I've been stuck on this for a while, here's my code, and the error is:

copy1-1.cpp:10:7: note: candidate function not viable: no known conversion from 'double' to 'double (*)[5]' for 1st argument
void funct (double A[2][5],int r,int c)
^

Code:

---

#include <iostream>using namespace std;
   
    void funct(double[2][5],int,int);
    int i,j,r,c;
    int n = 1;
    double A[2][5] = {{1.00,2.03,3.2,3,2.4},{.34,1.35,6.54,6,4.5}};
    double B[2][5];


    void funct (double A[2][5],int r,int c)
    {
    for (i=0;i<r;i++)
    {
    for(j=0;j<c;j++)
    B[i][j] = A[i][j];
    }
    }
    int main ()
    {
    funct(A[1][4],2,5);
    for (i=0;i<r;i++)
    {
    for(j=0;j<c;j++)
    cout << "A=" << A[i][j] << "\t" << "B =" << B[i][j];
    }
    return 0;
    }

---

Any help appreciataed

You need to pass address of an array, not value of its single element.

Code:

---

funct(A,2,5);

---

We can't use pointers if that's what you mean..

You probably can use pointers, except that you are not supposed to use pointer syntax to access the elements of the array. If so, then DRK's advice should work for you.

OK, thanks, my for loops still aren't being reached, I'll spend some more time on it, thanks again.

The for loop are being reached. The problem is that you have multiple distinct variables named r and c, and treating them as if they are equivalent. The r and c inside funct() are not the same ones being used by main().