Printable View
cout << "Do you wish to credit or debit your account? Enter C or D"<< endl;
string answer;
cin >> answer;
cout << "how much?"<<endl;
double amount;
cin >> amount;
if (answer== 'C') || answer== 'c')
//im getting the error
binary '==' : 'class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >' does not define this operator or a conversion to a type ac
Help!!! My other programs work like this!!!!
>if (answer== 'C') || answer== 'c')
Keep in mind that a string is not a character. The single quotes specify a test between a single character and answer, which is a string. Change the test to this and it will work:
if (answer== "C") || answer== "c")
-Prelude
Hasnt anybody noticed that theres a ) that shouldnt be there?
A ")" is missing...
>Hasnt anybody noticed that theres a ) that shouldnt be there?
Yes, that too. *blush*
-Prelude
if I remember right, (UNREGISTERED) the problem stats that you need to get both the type of transaction and the amount at the same time. ie C 124.56 (check of 124.56) this would lead to the variables of a char and an integer. oh and check it see if the char entered is an 'E' before getting the integer in. Then you use the if then statements for that char variable. till wednesday.