cout statement not working....i think...

ahhh...yeah this is really stupid but why is my program outputting zero for the variable pop?

Code:

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#include <iostream>

int main(void){

  using namespace std;

    //capture data
  cout << "Enter the world's population: ";
  long worlds_pop; cin >> worlds_pop;
  cout << "Enter the u.s. population: ";
  long us_pop; cin >> us_pop;

  //operate on data
  long pop = us_pop/worlds_pop;
 
  //ouput results
  cout << "The United States population is ";
  cout << pop << " % of the worlds population.";
  cout << endl;
  return 0;
}

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edit: yeah, it's obviously not std::cout, but I'm thinking its the way I'm operating on long?

Integer division. 1 / 2 -> 0
Kurt

riiight...int division results in an integer response with the remainder truncated. If the divisor was smaller than the numerator it would have given me an int, but that's not the case here....i see. this is an example in a book that wants both populations to be of type long...even if i have the answer as a float and its <1% the data would still be truncated. At least that's what I'm getting. Is there a way to get around that....while keeping both populations as long? Sorry if it's obvioius but I've been in thinking mode all day. I could just be tired :)

Then you should use

Code:

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long pop = 100 * us_pop/worlds_pop;

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Kurt

Quote:

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Originally Posted by ZuK

Then you should use

Code:

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long pop = 100 * us_pop/worlds_pop;

---

Kurt

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yeah thanks figured that out. long day.

You need to factor some float or double into the expression. You can do it by, for example

(us_pop * 1.0)/worlds_pop

or by casting the type of one variable

us_pop/static_cast<double>(worlds_pop)

The result will be a double, of course, so you have to cast it back to a long if you want to truncate it.