Preforming operations on an array

For my assignment I have to have an array with only zeros.

Code:

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int a[20] = { 0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0,  0 };

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Then I need to send it into a function that makes the array like this

Code:

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int a[20] = {0,1,2,3,4,5,6, ... , 19}

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Which I have done here

Code:

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int initialize(int a[], int n)

{
    int m = 0;
    int i;
   
    printf("\n");
    printf("Now the array is \n");
   
         
    for (i=0; i<20; i++ )
    { 
       
        a[i] = a[i] + m;
       
        m = m + 1 ;
       
        printf ("%3d", a[i]);
       
        }
       
       
}

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Now I need to do the following with the array.

I need to take whatever value is in each position and add that value to all of the previous values.

like this.

Code:

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a[3] = a[3] + a[2] + a[1] + a[0]

only for every a[i]

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I know that I can code this the long way, but I just can't see to be able to find out how to do this a better way.

Thanks.

by the way its my first post.

For the first one you could have just done:

Code:

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  for (i=0; i<20; i++ )
       a[i] = i;

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For the next one, you'll need to use a nested loop (a loop within a loop).