where do i define a struct in my code using an array class

is it any different when using a class in my code

my previous code i define my struct like this

Code:

---

#include <iostream>
#include <fstream>
#include <string>

struct{
          int type 1;
          string type2;
          double type 3;
          string type 4;
};

void print(){
                //code to print in here

};

int main(){

print();


}

---

but i have to use a class now

so my code looks something like this

Code:

---

#include <iostream>
#include <fstream>
#include <string>

using namespace std;



class Array_Class
{
    public:
       
        void Print();
       
    private://behavior


        int count;  //do I define the struct here
        int *A;




};

int main(){

print();

}

---

or do i still define it the same way at the top of my code.

The only difference is that in a struct all members are public by default.

In object oriented programming, the implementation of the class, the data of the class, should be private so that access to it and modifications to objects can be checked. The interface, the functions which provide access to data and modify data, should be public. Whether you declare a struct inside a class is up to you.

Your "previous example", as you've shown it, isn't valid code. The code you have now is just as good, in the sense that it won't compile either.

In C++, a class is the same as a struct, except that default access is private in a class and public in a struct.

If this doesn't seem helpful that is because you haven't really asked a question that is intelligible to anyone other than you. Read this link.

Quote:

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Originally Posted by c++noob145

do I define the struct here ... or do i still define it the same way at the top of my code.

---

The answer to that question is "No". You don't make a struct as well. The class is instead of a struct.