how to increment chars while skipping the first few

lets say that I want a char array that reads in chars but I want the first nine reserved for something else and I want first there to be one set of chars like input 13 output char 10 and I want to increment the chars when dealing with more than one while skipping the first nine like 14,14 = 11,11
how can I do this?

I'm pretty sure that I don't understand your problem but if you want to reserve the first nine characters of the array you could do something like:

Code:

---

#include <stdio.h>
#include <string.h>
 
#define SIZE 20

int main(void)
{
    char arr[SIZE];
    strcpy(arr, "reserved!");
    puts("Enter some text:");
    fgets(&arr[9], SIZE - 9, stdin);
    puts("\ncontents of arr:");
    puts(arr);

    return 0;
}

---

This will put 9 characters into the array, then reads from stdin and stores the input starting at the 10th position of the array.

Is this close?

Bye, Andreas

Thanks but not close
I guess I will have to read more books before I will be able figure this out if I ever do
I mean something like a=j and a different one ab=jk and abd = jkm

Quote:

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Originally Posted by Once-ler

Thanks but not close

---

Well there's a dis-incentive to bother helping you again.

How about posting some written examples of the kind of thing you're trying to do.

One vague description then a reply of "nope, not it" is not the way to get progress in any walk of life.

I was just telling him that it was not what I am looking for, I thanked him and was not rude

well then how about being more descriptive, and telling us, or better yet showing us what it is you want, instead of just "not it"

I am trying to show what I mean
j=a jk=ab jkmnop=abd a program that goes through chars and changes them to different chars sometimes with a few digits sometimes with a lot, I need some way of incrementing the correct number of digits

Sorry, but that looks like you fell asleep on the keyboard to me.

Wild guess time
You have
aaaaa
then you want
aaaab
until it gets to
aaaaz
and then you want
aaaba

Quote:

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Originally Posted by Once-ler

j=a jk=ab jkmnop=abd a program that goes through chars and changes them to different chars sometimes with a few digits sometimes with a lot, I need some way of incrementing the correct number of digits

---

If you don't tell us the general rules (which characters should be incremented by which amounts), we can only guess.

How about using a translation table/array, where you store for each character the new character:

Code:

---

#include <stdio.h>

int main(void)
{
    int translate[256] = {[106] = 97, 98, 99, 100};  // works only in C99 and later
    char *test = "jkmnop";

    printf("%s = ", test);
    for (int i = 0; test[i] != '\0'; i++)
        putchar(translate[(unsigned char) test[i]]);

    putchar('\n');
    return 0;
}

---

The idea is to use the character as index for the translation array. For example if the character is 'j' (decimal 106 in ASCII), translate['j'] == translate[106] == 97 == 'a'.
You have to do this for every character you want to translate.

Bye, Andreas

Is what you want something like this:

Code:

---

/* Start at ninth character */
int i = 9;
int ch;

/* Put input into String starting from the ninth character */
while ( (ch = getchar()) != '\n' && ch != EOF)
{
  String[i] = ch;
  i++;
}

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