What's the cause of this error message?

I get a compile error I can not figure out with this code:

In the .h file

Code:

---

template <class T> class ABC {

    private:

        struct node_t {
            T data;
            struct node_t *next;
        };

        node_t *new_node(T element);
};

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In the .cpp file as the first thing after the #includes:

Code:

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template <class T>
node_t *ABC<T>::new_node(T element) {
    struct node_t *node = new struct node_t;
    node->data = element;
    node->next = NULL;
    return node;
}

---

Code:

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ABC.cpp:17: error: expected constructor, destructor, or type conversion before ‘*’ token

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The file has about 200 lines of code and this section is the only part that generates an error (for now :tongue:).

Normally with templates both the declaration and implementation must be in the same compilation unit. Did you try to place the code in the second snippet in the .h file?

Also you may want to tell us what line in the snippet corresponds to the line 17 of your error message, after all you have several * in your snippet.

Jim

Quote:

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Originally Posted by jimblumberg

Normally with templates both the declaration and implementation must be in the same compilation unit. Did you try to place the code in the second snippet in the .h file?

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It started it's life as a .h file (because I'm lazy), now I have moved the implementation to a .cpp file. There are 12 other functions except this one that all compile without problem, I have added the template <class T> ABC<T>:: bit to all of them in the cpp file.

Quote:

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Originally Posted by jimblumberg

Also you may want to tell us what line in the snippet corresponds to the line 17 of your error message, after all you have several * in your snippet.

Jim

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Sorry, that's line 2 in the second code box above, the node_t *ABC<T> etc. bit. This function returns a pointer, to me it looks ok, but is there some other way I need to do it if templates are involved perhaps?

Quote:

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It started it's life as a .h file (because I'm lazy), now I have moved the implementation to a .cpp file.

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Templates require that both the definition and the implementation to be in the same compilation unit.


Try moving the implementation back into the .h file. Many times a template class is header only, no .cpp file required.

Jim

Quote:

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Originally Posted by jimblumberg

Templates require that both the definition and the implementation to be in the same compilation unit.

Try moving the implementation back into the .h file. Many times a template class is header only, no .cpp file required.

Jim

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But what exactly do you consider a single compilation unit? The .h file simply defines the class interface, I thought mixing implementation in the .h file was considered a cardinal sin. I have a pocket reference here that states:

Quote:

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Member functions defined outside of the template class in which they are declared must be parameterized as well. For example:

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Code:

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template <class Type>
bool Array<Type>::insert(const Type &element, int pos) {
...
}

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Which is what I have done for all other functions. Those compiles without errors as long as I add the template parameters like above.

Quote:

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I thought mixing implementation in the .h file was considered a cardinal sin.

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Not when dealing with templates.

Quote:

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Member functions defined outside of the template class in which they are declared must be parameterized as well.

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Quite true. Just like member functions of non-template classes defined outside the class must be properly parameterized.

Quote:

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But what exactly do you consider a single compilation unit?

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Usually a single compilation unit is one file. However you can use multiple files by including the implementation in the include file (after the class definition).

You may find this link informative Templates C++ Documentation, be sure you scroll down to the bottom of this page and read the section titled: "Templates and multiple-file projects".

Quote:

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Templates and multiple-file projects
From the point of view of the compiler, templates are not normal functions or classes. They are compiled on demand, meaning that the code of a template function is not compiled until an instantiation with specific template arguments is required. At that moment, when an instantiation is required, the compiler generates a function specifically for those arguments from the template.

When projects grow it is usual to split the code of a program in different source code files. In these cases, the interface and implementation are generally separated. Taking a library of functions as example, the interface generally consists of declarations of the prototypes of all the functions that can be called. These are generally declared in a "header file" with a .h extension, and the implementation (the definition of these functions) is in an independent file with c++ code.

Because templates are compiled when required, this forces a restriction for multi-file projects: the implementation (definition) of a template class or function must be in the same file as its declaration. That means that we cannot separate the interface in a separate header file, and that we must include both interface and implementation in any file that uses the templates.

Since no code is generated until a template is instantiated when required, compilers are prepared to allow the inclusion more than once of the same template file with both declarations and definitions in a project without generating linkage errors.

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Jim

Quote:

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Originally Posted by Subsonics

What's the cause of this error message?

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It looks like you use node_t as if it were in the global namespace or in scope, but actually the node_t struct is nested inside ABC, thus you should write:

Code:

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template <class T>
typename ABC<T>::node_t *ABC<T>::new_node(T element) {

---

Quote:

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Originally Posted by Subsonics

But what exactly do you consider a single compilation unit?

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A given source file with all headers (and to-be-included-only implementation files) included.

Quote:

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Originally Posted by Subsonics

The .h file simply defines the class interface, I thought mixing implementation in the .h file was considered a cardinal sin.

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Exceptions are made for inline functions and for templates (although there are exceptions to this exception as well).

Quote:

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Originally Posted by laserlight

It looks like you use node_t as if it were in the global namespace or in scope, but actually the node_t struct is nested inside ABC, thus you should write:

Code:

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template <class T>
typename ABC<T>::node_t *ABC<T>::new_node(T element) {

---

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Thanks, unfortunately that moved the problem on to other errors like:

error: expected initializer before ‘struct’
error: expected constructor, destructor, or type conversion before ‘->’ token

I will try to create a small compilable example that replicates this and get back.

Quote:

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Originally Posted by laserlight

Exceptions are made for inline functions and for templates (although there are exceptions to this exception as well).

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That's interesting, but is the idea that it's better to keep it separated (in case of templates) if possible?

Quote:

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Originally Posted by jimblumberg

Not when dealing with templates.

Quite true. Just like member functions of non-template classes defined outside the class must be properly parameterized.


Usually a single compilation unit is one file. However you can use multiple files by including the implementation in the include file (after the class definition).

You may find this link informative Templates C++ Documentation, be sure you scroll down to the bottom of this page and read the section titled: "Templates and multiple-file projects".

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Thanks, that's interesting but seemingly at odds with "The C++ programming language" Stroustrup.

Quote:

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Members of a template class are declared and defined exactly as they would have been for a non-template class. A template member need not be defined within the template class itself. In that case, it's definition must be provided somewhere else, as for non-template class members (§C.13.7). Page 330, 13.2.1

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I may try to just move the offending function to the header, if that helps. :)

Quote:

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Originally Posted by Subsonics

That's interesting, but is the idea that it's better to keep it separated (in case of templates) if possible?

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I think that that is a matter of subjective style.

Quote:

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Originally Posted by Subsonics

Thanks, that's interesting but seemingly at odds with "The C++ programming language" Stroustrup.

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It isn't: what you quoted does not say anything about whether the definition of the class template's member function should be in the same translation unit or not. What it does say is that it can be separate from the class template's definition, just as the definition of a class' member function can be separate from the class definition.

Quote:

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Originally Posted by laserlight

I think that that is a matter of subjective style.


It isn't: what you quoted does not say anything about whether the definition of the class template's member function should be in the same translation unit or not. What it does say is that it can be separate from the class template's definition, just as the definition of a class' member function can be separate from the class definition.

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True, but in contrast to the earlier quote it seems that way imo.

Quote:

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Because templates are compiled when required, this forces a restriction for multi-file projects: the implementation (definition) of a template class or function must be in the same file as its declaration.

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I have edited out most of the content of the files and still get the same error, these files should compile afaik.

ABC.h

Code:

---

#ifndef ABC_H
#define ABC_H

#include <cstddef>

template <class T> class ABC {

    private:

        struct node_t {
            T data;
            struct node_t *next;
        };

        node_t *new_node(T element);

};

#endif

---

.cpp

Code:

---

#include "ABC.h"

//template <class T>
//typename ABC<T>::node_t *ABC<T>::node_node(T element)
template <class T>
node_t *ABC<T>::new_node(T element) {
    struct node_t *node = new struct node_t;
    node->data = element;
    node->next = NULL;
    return node;
}

int main(void)
{
    return 0;
}

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Since the struct node_t is local to your class it can't be used outside the class. Therefore trying to return this structure from a class member function would be an error.


Jim

Quote:

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Originally Posted by jimblumberg

Since the struct node_t is local to your class it can't be used outside the class. Therefore trying to return this structure from a class member function would be an error.


Jim

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That makes sense, but the function is never used, and can't be used outside of the class, it's declared as private and is used as a utility function to make implementation less repetitive.

Quote:

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but the function is never used

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Then why have it?

Quote:

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and can't be used outside of the class

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Then you shouldn't need to return the structure.

The issue really is, "why are you defining the structure inside the class"? It really seems that this structure should be external to the class.

Jim

Quote:

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Originally Posted by jimblumberg

Then why have it?

Then you shouldn't need to return the structure.

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As I said, it's a utility (helper) function. Declaring it private is roughly equivalent with functions with file scope in C. Think of it this way, every time I need to add a node, I need to create a new instance of that struct, I can do it manually, or by calling this helper function. But never the less, it's internal to the class and part of the implementation.

Quote:

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Originally Posted by jimblumberg

The issue really is, "why are you defining the structure inside the class"? It really seems that this structure should be external to the class.

Jim

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Because the structure is a building block that should not be part of, and hidden from the interface. It's an internal implementation detail.

If the structure is internal to the class you can't use it as a return value, it doesn't matter if the member function is public, private, protected or whatever.

What do you plan to do with this return value? Normally a private member function will only work on either local variables or class member variables. So instead of returning a value, alter a class member variable.

Jim

Quote:

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Originally Posted by Subsonics

Thanks, unfortunately that moved the problem on to other errors like:

error: expected initializer before ‘struct’
error: expected constructor, destructor, or type conversion before ‘->’ token

---

Are you sure that you did it without any mistake?

This compiles fine.

ABC.h

Code:

---

#ifndef ABC_H_INCLUDED
#define ABC_H_INCLUDED

#include <cstddef>

template <class T> class ABC {

public:

    struct node_t {
        T data;
        struct node_t *next;
    };

    node_t *new_node(T element);

};


#endif // ABC_H_INCLUDED

---

.cpp

Code:

---

#include "ABC.h"

//template <class T>
//typename ABC<T>::node_t *ABC<T>::node_node(T element)
template <class T>
typename ABC<T>::node_t *ABC<T>::new_node(T element) {
    struct node_t *node = new struct node_t;
    node->data = element;
    node->next = NULL;
    return node;
}

int main(void) {
    return 0;
}

---

Quote:

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Originally Posted by jimblumberg

If the structure is internal to the class you can't use it as a return value, it doesn't matter if the member function is public, private, protected or whatever.

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That seems odd, the fact that it's private will prevent it from ever being called from the outside anyway. But, I may end up just returning void*, but as I said creating instances of the struct within the class can be done and is done.

Quote:

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Originally Posted by jimblumberg

What do you plan to do with this return value? Normally a private member function will only work on either local variables or class member variables. So instead of returning a value, alter a class member variable.

Jim

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Add it as a part in a linked data structure. The struct is local to the class, I also have class member variables but they are 100% unrelated to this issue.

Quote:

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Originally Posted by fightmx

Are you sure that you did it without any mistake?

This compiles fine.

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That's odd, what compiler are you using? I tried to copy/paste what you posted and compiled it:

Code:

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g++ paste.cpp

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And got these errors:

Code:

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paste.cpp:6: error: prototype for ‘typename ABC<T>::node_t* ABC<T>::new_node(T)’ does not match any in class ‘ABC<T>’
ABC.h:16: error: candidate is: void* ABC<T>::new_node(T)
paste.cpp:6: error: template definition of non-template ‘typename ABC<T>::node_t* ABC<T>::new_node(T)’

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I tested both using Visual Studio and MinGW (I'm using windows now).

Quote:

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Originally Posted by jimblumberg

If the structure is internal to the class you can't use it as a return value, it doesn't matter if the member function is public, private, protected or whatever.

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That is not true. For example:

Code:

---

template <class T>
class ABC {
private:
    struct node_t {
        T data;
        node_t* next;
    };
public:
    void foo(const T& element)
    {
        node_t node(new_node(element));
    }
private:
    node_t new_node(const T& element);
};

template <class T>
typename ABC<T>::node_t ABC<T>::new_node(const T& element) {
    node_t node;
    node.data = element;
    node.next = 0;
    return node;
}

int main()
{
    ABC<int> x;
    x.foo(123);
}

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By the way, this is C++, not C, so the struct node_t thing is an anachronism.