trouble passing parameter to function

I'm having some difficulty compiling the following code. When I run

Code:

---

void list_dir (char * dir_name)
{
    DIR * d;
    d = opendir (dir_name);
.....
}

int main (int argc, char *argv[])
{   
  list_dir (argv[1]);
    return 0;
}

---

my program compiles without issue, but when I try to pass a second parameter to the function of either argv[2] or *argv, the compiler is telling me too few parameters to function or expecting * when parameter is **, an example is....

Code:

---

void
list_dir (char * dir_name, char * newz)
{
    DIR * d;
  d = opendir (dir_name);
.....
}

int main (int argc, char *argv[])
{
    list_dir (argv[1], argv[2]);
    return 0;
}

---

Any suggestions on why the compiler doesn't accept how the second argument, argv[2], is being passed. Thanks!

looks correct to me. can you post the exact error message and the exact code rather than an excerpt. try to boil it down to a very simple example.

Is there a function prototype for list_dir before this?
If so maybe it's different from the function definition.

Indeed, the important bit is in precisely what is different between the example you post here and the real code.