Help with Program that only allows three tries

Hi so for this program it says:
1)Allow the user only three chances to enter the correct number.
2)The program should stop if the user doesn't enter the correct value after the third try
3) The program should stop if the user guess correctly(and is less than 3 tries)

here is the code:

Code:

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#include<stdio.h>#include<stdlib.h>
#include<string.h>
#include<time.h>


// Declaration Section
int num;
int guess;


void pauseProgram()
{
    printf("\nPress any key to continue...");
    getchar();
    }
   
    // Function Title
    void title(char*programTitle)
    {
          int len=strlen(programTitle);
          system("cls");
          printf("\n");
          for(int i=1;i<40-len/2;i++) printf("");
          printf("%s\n",programTitle);
          }
         
          // User lnput
          void userlnput()
          {
              title("Random Number");
              printf("\nEnter a number between 1 and 100:");
              scanf("%d",&guess);
              getchar();
              }
             
              //Funcion displayRand
              void displayRand()
              {
                    /* The following 2 lines are needed for generating
                    dufferent random numbers for each execution.
                    Simple "srand()" seed: just use "time()"
                    */
                    unsigned int iseed= (unsigned int)time(NULL);
                    srand(iseed);
                   
                    num= rand()%100;
                    num= num+1;
                    title("Random Number");
                    if(guess>num)
                    printf("\nCome down!\n");
                    else if(guess<num)
                    printf("\nWay down there?\n");
                    else
                    printf("\nRight on!\n");
                   
                    pauseProgram();
                    }
                   
                    // Main Program
                    int main()
                    {
                        do
                        {
                              userlnput();
                              displayRand();
                              if(num==guess)
                              {
                                            break;
                                            }
                                            }while(1);
                                            }

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I am struggling to find the part that you describe us the error, or why you are not happy with the code....

If i read the code i might find out myself, but this would be unfair i think :)

Quote:

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Originally Posted by std10093

I am struggling to find the part that you describe us the error, or why you are not happy with the code....

If i read the code i might find out myself, but this would be unfair i think :)

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Basically in this program you have to guess the correct number between 1-100. However at this moment the user gets an infinite amount of guesses.

I want to make it so that they only have 3 guesses. If they get it right the program says "Good job", and even if they dont get it right in 3 guesses it says "Try next time"

I was wondering if someone could tell me the code I would have to write to make this work or maybe the location in which i'm supposed to put it

Thanks

vololo: if you're using vim try, at command mode, pressing gg=G.

Quote:

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Originally Posted by vololo

I want to make it so that they only have 3 guesses.

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Thank you :)

You want the loop in main to be executed maximum three times and at least once! Good choice of the do-while loop..
So i will make an example of loop i want to run maximum 5 times and at least one.I want the loop to stop executed if the user types 5.

Code:

---

#include <stdio.h>

int main(void)
{
    int a;
    int counter = 0;

    do{
        /* Maximum iterations allowed */
        if(counter == 5 )
                break;
        /* Increment counter by one */
        counter++;
        /* Read input */
        scanf("%d",&a);
    /* Check if the user typed 5 */
    }while(a != 5 );

    return 0;
}

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Now try to modify your code :)