Read inputs for an dynmaically allocated array

I want to read user's input for my array using pointers, allocated space, read elements and return pointer.

my function is called read:

Code:

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double read *read_vector (int n) // n is the size of array, which user will enter

int *vec = (int *) malloc (sizeof(int)*n);
int i;
for (i=0; i<10; i++)
            vec[i] = n;
return vec;

}

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but this code is not working, giving me segmentation fault, any help please?

this is part of the main function i am using to read it:

Code:

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int n;
  double *vector;
  /* Vector */
  printf("Vector\n");
  printf("Enter number of entries: ");
  scanf("%d",&n);
  printf("Enter %d reals: ",n);
  vector = read(n);

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Your *vec variable should be a double pointer since that is what you are returning and your for loop should probably iterate from i to n, not 10. At the moment your function isn't actually reading anything it just initializes the array with n, but I guess you know that.

how do I read the inputs in?

changed some things:

Code:

---

double *read_vector(int n){
double *vec = (double *) malloc (sizeof(double)*n);
int i;
for (i=0; i<n; i++)
      vec[i] = n;
      return vec;
}


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now how do i store the users inputs?

this is my print vector function:

Code:

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/* Print a vector with n entries pointed to by vec. */
void print_vector(int n, double *vec){
int i;
for (i=0; i<n; i++) {
    printf("%d", vec[i]);
}



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is this correct?

my read_vector is not even letting me enter the numbers for some reason.

Quote:

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Originally Posted by Lina_inverse

my read_vector is not even letting me enter the numbers for some reason.

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Because you don't read any numbers. You just assign "n" to each member of "vec".

For reading user input you probably want to use scanf().

Bye, Andreas