Resistor value to color code and vice versa

I'd like to thank you all for your time and help in advanced much appreciated.

Microsoft Visual Studio 2012
C++ Console Application

What my program is to do:
-ask user for value ex. 200 ohms
- output the value in color ex brown black brown
and vice versa
-ask user for color ex brown black brown
-output the value ex 200 ohms

a few background summary:
I'm very new to C++(2 days) i have self taught myself c++ enough to make my very first working program. i got it to output the value based on the color numbers entered. basically am trying to make a resistor color code calculator.

My problem:
- it only outputs the value based on color numbers
how do i make it output value in colors?
- is there better ways of doing this?

Code:

---

#include <iostream>
#include <cmath>
using namespace std;


int main() {
    double colornum,multiplier;


    cout<<"0 = black"<<endl;
    cout<<"1 = brown"<<endl;
    cout<<"2 = red"<<endl;
    cout<<"3 = orange"<<endl;
    cout<<"4 = yellow"<<endl;
    cout<<"5 = green"<<endl;
    cout<<"6 = blue"<<endl;
    cout<<"7 = violet"<<endl;
    cout<<"8 = grey"<<endl;
    cout<<"9 = white" <<endl<<endl;


    cout<<"Enter 1st & 2nd band color numbers: ";
    cin>>colornum;
    cout<<"Enter 3rd band color number(Multiplier): ";
    cin>>multiplier;


    cout <<"The color code of a "<<colornum<<multiplier<< " resistor is: ";


    if ( multiplier == 0) {
        multiplier = colornum * pow( 10,0 );
    } else if ( multiplier == 1 ) {
        multiplier = colornum * pow( 10,1 );
    } else if ( multiplier == 2 ) {
        multiplier = colornum * pow( 10,2 );
    } else if ( multiplier == 3 ) {
        multiplier = colornum * pow( 10,3 );
    } else if ( multiplier == 4 ) {
        multiplier = colornum * pow( 10,4 );
    } else if ( multiplier == 5 ) {
        multiplier = colornum * pow( 10,5 );
    } else if ( multiplier == 6 ) {
        multiplier = colornum * pow( 10,6 );
    } else if ( multiplier == 7 ) {
        multiplier = colornum * pow( 10,7 );
    } else if ( multiplier == 8 ) {
        multiplier = colornum * pow( 10,8 );
    } else {
        multiplier = colornum * pow( 10,9 );
    }
    cout <<multiplier<<endl;
    return 0;
}

---

Notice that

Code:

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cout <<"The color code of a "<<colornum<<multiplier<< " resistor is: ";

---

will print the value of colornum and multiplier with no space between them.For example if colornum=2 and multiplier=5 it will output The color code of a 25 resistor is:

As for your problem ,i do not understand what you mean :/

am trying to make my program output the colors rather then the numbers

resister references:
http://www.dannyg.com/examples/res2/resistor.htm
Electronic color code - Wikipedia, the free encyclopedia

the basic calculation is

color1color2 x 10^multiplier

12 x 10^2 = 1000 ohms (1k ohms) color = brown black red
1 being brown
2 being red
multiplier being red which is 2

I cannot load both pages for some reason(mine problem i would say).

If i input 0 2 i get the output

Code:

---

Enter 1st & 2nd band color numbers: Enter 3rd band color number(Multiplier): The color code of a 02 resistor is: 0

---

What do you want the output to be?Just give me an example please :)

the first input asked the user for 2 values from the color code number list no spaces btw all stuck together

cout<<"0 = black"<<endl;
cout<<"1 = brown"<<endl;
cout<<"2 = red"<<endl;
cout<<"3 = orange"<<endl;
cout<<"4 = yellow"<<endl;
cout<<"5 = green"<<endl;
cout<<"6 = blue"<<endl;
cout<<"7 = violet"<<endl;
cout<<"8 = grey"<<endl;
cout<<"9 = white" <<endl<<endl;

Say i enter 10 for brown and black

then it will ask the user for a third band color

say i enter 2 for red

output is 102 which should be brown black red

i want the output to be the name of the color relating to the numbers the user entered.

OUTPUT:
a 102 resistor is brown black red

Sorry for my difficulty to understand .

So what you want to do is to isolate every digit of the result and then make an if-else structure in order to print the colors.

I made an example (in c by accident.If this bothers you tell me to convert it to c++).The example has more things that you need,because i wanted to show you how the mod and division are used to extract the digits of a number.Surely this algorithm can be way better.

Code:

---

#include <stdio.h>

int main(void)
{
        int n=152;
        int a,b,c,d,f,g,z;
        a=n/100;
        b=n/10;
        c=n/1;
        printf("a= %d  b = %d  c=%d\n",a,b,c);
        d=n%100;
        f=n%10;
        g=n%1;
        printf("with mod->d= %d  f = %d  g=%d\n",d,f,g);
        z=b%10;
        printf("z=%d\n",z);
       
        if(a==0)
        {
                printf("black\t");
        }
        else if(a==1)
        {
                printf("brown\t");
        }
        ...
       
        return 0;
}

---

Np my problem is actually pretty hard to explain and understand as well but yes that's exactly what i want to do :)
my compiler can't run C can you pleas convert it to c++ if its not too much trouble.

Code:

---

#include <iostream>
using namespace std;

 
int main(void)
{
    int n=152;
    int a,b,c,d,f,g,z;
    a=n/100;
    b=n/10;
    c=n/1;
    cout<<"a= "<< a <<"  b = "<< b <<"  c= " << c <<endl;
    d=n%100;
    f=n%10;
    g=n%1;
    cout<<"with mod->d= " << d <<"  f = "<< f <<" g= "<< g <<endl;
    z=b%10;
    cout<<"z = "<< z <<endl;
   
    if(a==0)
    {
        cout<<"black    ";
    }
    else if(a==1)
    {
        cout<<"brown    ";
    }
    ...
   
    return 0;
}

---

hope this helps :)

Could you help me understand this please,what do you mean by "pow()" in your code?

Quote:

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Originally Posted by Aslaville

Could you help me understand this please,what do you mean by "pow()" in your code?

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It is a function :)

pow - C++ Reference

Is that code compiling in your compiler?Mine is developing some crazy things.Am on Microsoft Visual 2010

Quote:

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Originally Posted by Aslaville

Is that code compiling in your compiler?

---

If you are referring to the code of post #1,yes it compiled :)

What errors do you get?

It simply says that the 'pow' identifier is undefined

Have you included this library <cmath> ? :)

yes of course.I do not know what is wrong with the compiler.It is developing about six hundred lines of different code when I compile and try to get the error from the output section but the same code compiled on Code::blocks.I did not however know of the function prior to this conversation.Thanks for the update.