User defined number of columns?

How would you go about assigning a table of data a specific number of columns, by a user defined function?

for example if you had:

Code:

---

#include <stdio.h>
#include <stdlib.h>

int columns, i;

int main()
{

printf("\nEnter number of columns [1 to 10]: ");
scanf("%d", &columns);

for (i=0; i<15; i++)
printf("%d ", i);

}

---

How would you modify this so that the variable 'columns' was the amount of entries in the line before a new line began. So say you entered 8, the output would be..

0 1 2 3 4 5 6 7
8 9 10 12 13 14

Thanks in advance!

1. Create a 1d array with as many rows as you want. Make it an array of pointers.
2. Dynamically make a new array by using the malloc() function and put the address of it in the first element in the array of pointers.

I think he just wants to print some numbers in a given number of columns, not create a new data structure.

It's best not to use global variables unless there's a good reason.

Columnation can be implemented like this:

Code:

---

#include <stdio.h>

int main(void) {
    int columns, n, i;

    printf("Columns: ");
    scanf("%d", &columns);

    printf("Numbers: ");
    scanf("%d", &n);

    for (i = 0; i < n; i++) {
        printf("%3d ", i);
        if ((i + 1) % columns == 0 && (i + 1) < n)
            putchar('\n');
    }
    putchar('\n');

    return 0;
}

---