expected expression before ')' token

hi i am new to c, i keep getting this error. ":32: error: expected expression before ')' token"

here is my code.

Code:

---

typedef struct{
    char* name;
    int comValue;
}comName;


typedef struct{
    comName* comName;
    struct node *next;
}node;


void insertNode(void){
    node *newNode = (node*)malloc(sizeof(node));
   
    //initialize node
    newNode->next = NULL;
   
32    newNode->comName= (newNode*)malloc(sizeof(comName));
       
}

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THANK YOU

newNode is the name of a variable, not the name of a type. A type conversion as in "(newNode *)" requires the name of a type.

Unrelated to your problem .... it is a really bad idea, unless you enjoy the prospect of confusing yourself in future, to have variable names the same as type names.

Also, conversions of the return value from malloc() are not necessary. But you must #include <stdlib.h>

thank you grumpy.
yes i did include stdlib.h,, i just forgot to paste it in the forum...

now that i fixed that problem, i keep getting the error, ":32: error: 'comName' undeclared (first use in this function)"..!

thanks

Code:

---

    newNode->comName= (newNode*)malloc(sizeof(comName));
                                              ^^^^^^^  <=== THIS comName

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haha,, thanks guys... i got confused for a second..! :DDD

Quote:

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Originally Posted by qny

Code:

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    newNode->comName= (newNode*)malloc(sizeof(comName));
                                              ^^^^^^^  <=== THIS comName

---

---

And that's precisely why you don't have things with the same name ;-D

I'm new too by the way! I'm enjoying programming in C, but have had a lot of problems.

Hey, The Doctor, I am also in Perth. Small world. :D

And "expected expression before ')' token" is common for me too, as well as ) or ;