Pointers make sense

Reading pointers finally make sense and I just want to share and be told off if I'm wrong. It's all down to the names and the equals sign!
So,
& gives the reference,
* is the dereference.

These are inverse operators so applying both is like doing nothing. A lot like multiply by 2 and divide by 2 or add two and subtract 2. More formally, a/a = 1 and 1 + a - a = 1. So following on *& = 1.

Consider the snippet from Cprogramming.com pointers,

Code:

int x; // A normal integer int *p; // An pointer to an integer p = &x; // Assign the address of value x to p cin >> x; // Give x a value cin.ignore(); // Remove the carriage return from the entry cout << *p << "\n"; // This will print the value entered for x

Now the bit that clicked for me was this,

Code:

p = &x

so if I apply the * operator, I must apply to both sides

Code:

*p = *&x

but the operators are inverses on the right hand side

Code:

*p = x

the last line would act like

Code:

cout << x << "\n";

and it does.
Hopefully someone more practiced can say if this is a good schematic view. I've not seen this mentioned elsewhere and hope it helps someone who is stuck with pointers but thinks like a mathematician, got to be one or two out there.

Yes, I suppose that works. Just remember that & gives the address, not the reference (reference is an entirely different thing).

It seems that you are know learning about pointers.I am i student(i am learning too) so when i want to be sure about pointers and references i use a paper and a pencil.I draw small boxes that stand for memory cells.Then i draw arrows(from boxes that are hosting pointers) to point in other boxes.However because an image equals to 1000 words,see that

Code:

int x=2; int *p; p=&x;

Image(my intention was to upload one but it was too large)
Let adress of x to be 100

p x
+----+(space.)+--+
|100 |-------->| 2 |
+----+(space.)+--+

So if you follow this tactic then the most compilcated issues will be resolved easily :)