how to make a counter

Ok, guys I had an idea, I want to make a program that counts how many characters you type, but I don't know how to make an input of one character at a time without pressing enter, neither how to make a display that changes every time you press a key. so far this is what I got of code

Code:

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#include <stdio.h>
#include <stdlib.h>

int cont;
char sig[1];

int main(void){
printf("start counting");
    for(;;){
    cont=0;
    scanf("%c", sig);
    if(sig!="q"){
        cont++;}
    else{break;}
}
printf("%d", cont);
}

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I thought it would work fine but it doesn't quit if I press "q", plus I have to pres enter for this program to count one character.

There is no way to do that in standard C unfortunately. Input only goes into C's IO buffers after you press enter.

cyberfish is right because it the behavior is system dependent so you have to use system API's to do what you want. if you are using Visual studio on windows, you can use "conio.h" to get that behavior. look up _kbhit and getch. if you are on Linux you can set your terminal to raw mode using the termios functions.. google 'linux termios' and look at the function cfmakeraw. if you are on apple, i have nothing for you.

Quote:

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Originally Posted by Tollme

Ok, guys I had an idea, I want to make a program that counts how many characters you type

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If you only want to count the characters and not the number of key presses, it's rather easy:

Code:

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#include <stdio.h>

int main(void)
{
    int count = 0;

    printf("Start counting (Quit with CTRL-D in Unix/CTRL-Z in Windows)\n");
    while (getchar() != EOF)
        count++;

    printf("\nYou've entered %d characters\n", count);

    return 0;
}

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Code:

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    if(sig!="q"){

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That's just wrong in any case because if you want to compare characters you have to use single quotes. For comparing strings you have to use strcmp.

Bye, Andreas