Taking the Smallest from a LL

Below is my Homemade Linked List.

I need to implement a method in the class that will return an
applicant with the smallest number in their date attrib.

Applicants with a date of zero don't count and once an applicant is returned it's date should be set to zero indicating that i've hired them ( hopefully as a programmer :) )

The Method (doesn't work):

Code:

---

        applicant hire(void){
               
                applicant tmp;
                cur=head;

                do{
                        tmp=cur->data;
       
                        if(cur->data.date)
                                cur->data.date=0;

                        goNext();

                }while(!cur->data.date);


                return tmp;

        }

---

The Structure:

Code:

---

struct applicant {
        char name[61];  // applicant's name
        char phone[21]; // phone number
        long date;      // date of application in yyyymmdd
       
        operator=(const applicant rhs){
                strcpy(name, rhs.name);
                strcpy(phone, rhs.phone);
                date = rhs.date;
        }

};

struct Node{
        applicant data;
        Node *next, *prev;

        Node(){next=prev=NULL;};
       
        Node(applicant data){
                this->data = data;
                next = prev = NULL;
        }
};



class jobfile:public fstream{

protected:
        int success, records;
        char FileName[30];
        Node *cur, *tail, *head;
               
public:

        //Misc. Methods

---

You need to put some form of testing in the loop.
eg:

Code:

---

        applicant hire(void){
               
                cur=head;
                applicant smallest = cur->data;

                do{
                        if ((cur->data.date != 0) && (cur->data.date < smallest.date))
                                smallest = cur->data;

                        goNext();

                }while(!cur->data.date);


                return smallest;

        }

---

Code:

---


#include<iostream.h>
#include<fstream.h>
#include<string.h>


struct applicant {
            char name[61];  // applicant's name
            char phone[21]; // phone number
            long date;      // date of application in yyyymmdd format

                        applicant(){}
                        applicant &operator=(applicant x){
                                date=x.date;
                                strcpy(name,  x.name);
                                strcpy(phone, x.phone);
                        return *this;
                        }

    };


int main(void){

        fstream fs("2111112.aaa", ios::binary);

        applicant x;
                x.date=9;
                strcpy(x.name,  "Chief");
                strcpy(x.phone, "13281");


cout<<endl<<"--------------"<<endl<<"Name="<<x.name<<endl<<"Date="<<x.date<<endl
<<"Phone="<<x.phone<<endl<<"--------------"<<endl;

        fs.seekp(ios::beg);
        fs.write( (char*)&x, sizeof(applicant) );


        fs.seekg(ios::end);

        int recs = ( fs.tellg() / sizeof(applicant) );
        cout<<"recs="<<recs<<endl;


        applicant in;
        fs.seekg(ios::beg);
        fs.read((char*)&in, sizeof(applicant) );


cout<<endl<<"--------------"<<endl<<"Name="<<in.name<<endl<<"Date="<<in.date<<en
dl<<"Phone="<<in.phone<<endl<<"--------------"<<endl;

return 0;
}

---

Open the file like this -

Code:

---


            fstream fs("2111112.aaa", ios::in | ios::out | ios::binary);

---

please post your whole code or/and errors

It's alright pode, ginoitalo solved my problem,

I though an fstream's default would be ios::out and ios::in

Thanks.