Why is this simple c program not working ?

So I wrote this program that asks for your details. The part where it asks for details works , but then it fails to show the details in the last bit of the program.
It crashes .. why ?

Code:

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#include <stdio.h>
#include <ctype.h>




int main() {

char name = '\0';
char surname = '\0';
int passport=0;


printf("Enter name: ");
scanf("%s", &name);


printf("Enter surname ");
scanf("%s", &surname);

printf("Enter passport: ");
scanf("%d", &passport);


printf("Your details are: name:%s , surname:%s , passport:%d", name,surname,passport);
}



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1) main returns an int
2) you are trying to read strings into variables that can store and do store only one char.
3) you are not calling scanf correctly, remove the & when you are reading char arrays.
4) in fact, Don't use scanf to read in strings, because you can overflow them. Use fgets().

so what should I write instead of int ? .. and should I declare char like char[10] ?

> so what should I write instead of int ?
Huh? No, main is supposed to return an int. You forgot to.

> and should I declare char like char[10] ?
Right.

What do you mean by returning an int ? .. sorry for my ignorance but I am new to C.

Your main function says it returns an int (which is correct):

Code:

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int main {

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But you NEVER return an int from it.

Literally, at the end of main, you should have something like:

Code:

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return 0;

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The others are all valid points too and the REAL cause of your problem. You're obviously NOT compiling this with warnings turned on, so you've missed so many problems before you even start.