If statement is falling through. Not waiting for second user input

Does anyone know why this is falling through?
the second printf statement displays however, program terminates without waiting for input character from user. I've tried fflush(stdin) but with no luck

Code:

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#include <stdio.h>

int main()
{
        char ch;
        int n;
       
        printf("user data: ");
        scanf("%d",&n);
       
        if(n==5)
        {
                /*obtain more data from user*/       
                printf("Enter more Data? ");
                scanf("%c",&ch);
        }

return(0);
}

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When the user enters the number, the newline is left in the input buffer. It is then read when you use %c with the next scanf. An appropriate solution is to read and discard that newline character immediately after reading the number.

thanks for the quick reply.
I've tried to clean out the buffer by fflush(stdin), however, the problem still persists.
Another command I tried was flushall() but im getting an error

Code:

---

#include <stdio.h>

int main()
{
        char ch;
        int n;
       
        printf("user data: ");
        scanf("%d",&n);fflush(stdin);  /*also tried flushall()*/
       

        if(n==5)
        {
                /*obtain more data from user*/       
                printf("Enter more Data? ");fflush(stdin);
                ch=getchar();
        }


return(0);
}

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Quote:

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Originally Posted by bos1234

I've tried to clean out the buffer by fflush(stdin), however, the problem still persists.

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fflush(stdin) results in undefined behaviour. I would expect something like this:

Code:

---

#include <stdio.h>

int main()
{
    int ch;
    int n;

    printf("user data: ");
    scanf("%d", &n);
    while ((ch = getchar()) != '\n' && ch != EOF);

    if (n == 5)
    {
        /* obtain more data from user */
        printf("Enter more Data? ");
        ch = getchar();
        printf("You entered: %c\n", ch);
    }

    return 0;
}

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