Integer constant is too large for 'long' type. How do I fix it?

Hi, so I'm trying to make a program that will display the digits of up to a maximum of 10 digit number in column form. I used "long long int" since it's a huge number. And for my printf and scanf I used "%lld". I get an error pointing at my 'for loop' line saying "Integer constant is too large for 'long' type". I use Quincy on Windows 7. Here is the code:

Code:

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#include <stdio.h>
main ()
{
    long long int n;
    long long int digit;
    long long int i=10,j=1;
   
    printf ("Enter a positive integer up to a maximum of 10 digits: ");
    scanf ("%lld",&n);
    printf ("\n");
   
    for (i;i<=10000000000;i*=10)
    {
        digit=(n%i)/j;
        printf ("%lld \n",digit);
        j*=10;
    }
}

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Thanks!

Also, it all works well, if I change the limit for i to 1 and 9 zeroes. If I do 10 zeroes, I get the error :(

Try writing
for (i;i<=10000000000LL;i*=10)

Whoah! Siiick! Thanks a lot! :D :D :D
We haven't learn any of this in class, but that was the problem. Works well :)
Thank you so much!

@y2r another option is to use and array to store the characters and then accessing the characters the way u want.

Quote:

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Originally Posted by Nyah Check

@y2r another option is to use and array to store the characters and then accessing the characters the way u want.

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Oh yeah, I've heard of arrays. This friend of mine always talks about that, but we haven't studied them yet in class. But when I learn it, then it would be much easier I would assume. Thanks :)